1
我最近問了一個關於如何Save a list with nested elements to XML的問題,但現在我正在嘗試爲該類編寫加載程序並遇到問題。使用LiNQ加載嵌套的XML
我試圖扭轉給出的答案(謝謝Jon)。
我相信我的核心LINQ查詢是好的,這是我正在努力的遞歸。 這裏是我到目前爲止的代碼(爲清晰起見,我已經發布了整個CPP爲是)
/// <summary>
///
/// </summary>
public class ErrorType
{
List<ErrorType> _childErrors;
public String Name { get; set; }
public bool Ignore { get; set; }
public List<ErrorType> ChildErrors { get; protected set; }
}
/// <summary>
///
/// </summary>
public class ErrorList
{
public List<ErrorType> ChildErrors { get; protected set; }
/// <summary>
///
/// </summary>
/// <param name="xml"></param>
public void FilterErrors(XElement xml)
{
//Convert to ErrorList
//Write back out to XML but not writing out anything with errors
//Send XML on its way
}
/// <summary>
///
/// </summary>
/// <param name="el"></param>
/// <returns></returns>
private XElement ErrorListToXml(ErrorList el)
{
// Need to declare in advance to call within the lambda.
Func<ErrorType, XElement> recursiveGenerator = null;
recursiveGenerator = error => new XElement
(error.Name,
new XAttribute("Ignore", error.Ignore),
error.ChildErrors.Select(recursiveGenerator));
var element = new XElement
("ErrorList",
ChildErrors.Select(recursiveGenerator));
Console.WriteLine(element);
return element;
}
/// <summary>
///
/// </summary>
/// <param name="xd"></param>
/// <returns></returns>
private ErrorList FromXmlToErrorList(XElement xd)
{
//Prepare lambda
Func<ErrorType, XElement> recursiveGenerator = null;
recursiveGenerator = error => new List<ErrorType>
(error.Name,
new XAttribute("Ignore", error.Ignore),
error.ChildErrors.Select(recursiveGenerator));
List<ErrorType> typeList = (from error in xd.Descendants()
select new ErrorType
{
Name = error.Value,
Ignore = bool.Parse(error.Attribute("Ignore").Value),
ChildErrors= error.Elements().Select()
}).ToList<ErrorType>();
ErrorList el = new ErrorList();
el.ChildErrors = typeList;
return el;
}
/// <summary>
///
/// </summary>
public void Save()
{
XElement xml = ErrorListToXml(this);
xml.Save("errorlist.xml");
}
public void Load()
{
}
}
三江源
這個工作非常漂亮三江源。我不完全確定它是如何工作的,因爲它從來沒有明確地設置孩子? – Chris 2009-06-02 14:21:24
構造函數本身通過迭代「children」參數,它是(幕後)迭代器遍歷xml ... – 2009-06-02 14:26:47