1
該代碼在我的控制器插入字節數組冬眠
FileInsertion fileInsertion = new FileInsertion();
FileUpload fileUpload = new FileUpload();
fileUpload.setFilename((InputStream) new ByteArrayInputStream(byteArray));
//byteArray is the file converted into a byte[]
fileInsertion.insertFile(fileUpload);
//the following happens in a separate method
trns = session.beginTransaction();
session.save(fileUpload);
session.getTransaction().commit();
Hibernate映射文件
<hibernate-mapping>
<class name="com.sort.process.FileUpload" table="fileupload">
<meta attribute="class-description">
This class contains the file upload detail.
</meta>
<id name="Id" type="int" column="Id">
<generator class="increment" />
</id>
<property name="filename">
<column name="filename" />
</property>
</class>
</hibernate-mapping>
我的目標是插入一個文件到一個數據庫表在該地方的BLOB對象。 但是我得到這個
Initial SessionFactory creation failed.org.hibernate.MappingException: Could not determine type for: java.io.InputStream, at table: fileupload, for columns: [org.hibernate.mapping.Column(filename)]
我嘗試了上面使用ByteArrayInputStream
代替InputStream
,卻徒勞無功。 任何人都可以讓我知道我的代碼中的錯誤是什麼?
在此先感謝
非常好,謝謝你工作得很好。我也跟着命名方法'setFile(...)'和'getFile()'的提示 – Freakyuser