Django表格2：LinkColumn

Question

我正在使用django-tables2來渲染我的應用程序表。我需要將包含鏈接<a> </a>的列添加到對象。

這裏是我的代碼：

# Extract of myapp views.py 

class ScanView(View): 
    template_name = 'scanner/scan.html' 

    def get(self,request, *args, **kwargs): 

     scans = Scan.objects.all().order_by('-last_date') 
     scans_tb = ScanTable(scans, prefix="1-") 
     RequestConfig(request, paginate=False).configure(scans_tb) 
     context = {'scans_tb': scans_tb} 

     return render(request, self.template_name, context) 


class ScanDetailView(View): 

    template_name = 'scanner/detail.html' 

    def get(self,request, scan_id): 
     scan = get_object_or_404(Scan, pk=scan_id) 
     context = {'scan': scan,} 

     return render(request, self.template_name, context) 

#extract of urls.py 

    url(r'^scan$', views.ScanView.as_view()), 
    url(r'^scan/(?P<scan_id>\d+)/$', views.ScanDetailView.as_view(), name='detail'),) 

#Extract of tables.py 

class ScanTable(tables.Table): 
    link = tables.LinkColumn('detail', args=[tables.A('pk')]) 

    class Meta: 
     model = Scan 
     attrs = {'class':'paleblue'} 

有一個名爲link列，但用什麼也沒有。我沒有看到我錯過了什麼，有人可以幫助我嗎？

謝謝！

Answer 1

Django-tables2使用該列的名稱來查找要在模型上顯示的值。你的模特有link字段嗎？如果沒有，這將是空白的。或者，您可以在列上提供'默認'屬性，即

class ScanTable(tables.Table): 
    link = tables.LinkColumn('detail', args=[tables.A('pk')], default='Link') 

    class Meta: 
     model = Scan 
     attrs = {'class':'paleblue'}