我想通過php的PDO類(mysql驅動程序)進行搜索。我有以下查詢與MySQL客戶端工作(表名稱更改爲保護無辜者):PHP PDO準備語句 - MySQL LIKE查詢
SELECT hs.hs_pk,
hs.hs_text,
hs.hs_did,
hd.hd_did,
hd.hd_text,
hv.hv_text,
hc.hc_text
FROM hs
LEFT JOIN hd
ON hs.hs_did = hd.hd_did
LEFT JOIN hd
ON hd.hd_vid = hv.hv_id
LEFT JOIN hc
ON hd.hd_pclass = hc.hc_id
WHERE hs.hs_text LIKE "%searchTerm%"
LIMIT 25;
不管我用搜索詞的這就像一個魅力。然而,當我轉向PHP時,我無法讓它返回任何東西。我嘗試了幾種不同的語法,看起來合乎邏輯,但我沒有嘗試過。這裏是我的現有代碼:
$handle = fopen('/foo/bar/test.log', 'w+');
fwrite($handle, "doSearch, with search term: $searchTerm\n");
$sql =
'SELECT hs.hs_pk,
hs.hs_text,
hs.hs_did,
hd.hd_did,
hd.hd_text,
hv.hv_text,
hc.hc_text
FROM hs
LEFT JOIN hd
ON hs.hs_did = hd.hd_did
LEFT JOIN hd
ON hd.hd_vid = hv.hv_id
LEFT JOIN hc
ON hd.hd_pclass = hc.hc_id
WHERE hs.hs_text LIKE :searchTerm
LIMIT 25';
try {
$dbh = new PDO('mysql:host=localhost;dbname=awdb', "user", "password");
fwrite($handle, "connected to DB\n");
$prep = $dbh->prepare($sql);
$ret = $prep->execute(array(':searchTerm' => '"%'.$searchTerm.'%"'));
while ($row = $prep->fetch(PDO::FETCH_ASSOC)) {
$i++;
$result[$i]['subText'] = $row['hs_pk'];
$result[$i]['subText'] = $row['hs_text'];
$result[$i]['subDid'] = $row['hs_did'];
$result[$i]['devDid'] = $row['hd_did'];
$result[$i]['devText'] = $row['hd_text'];
$result[$i]['vendorText'] = $row['hv_text'];
$result[$i]['classText'] = $row['hc_text'];
}
$dbh = null;
}
catch (PDOException $e) {
print "Error!: " . $e->getMessage() . "<br/>";
die();
}
我試過以下,以及(SQL WHERE子句&製備型>執行行是所有變化):
WHERE hs.hs_text LIKE CONCAT(\'%\', ?, \'%\')
$ret = $prep->execute(array($searchTerm));
WHERE hs.hs_text LIKE "%:searchTerm%"
$ret = $prep->execute(array(':searchTerm' => $searchTerm));
WHERE hs.hs_text LIKE ":searchTerm"
$ret = $prep->execute(array(':searchTerm' => '%'.$searchTerm.'%'));
等等
這可能只是一個轉置問題,但你有沒有封閉的SQL語句 - 你需要把一個單引號(')在它的結尾。 –
這是一個換位問題。如果我忘記了'我確信PHP會完全嚇壞了,哈哈。儘管感謝您的快速回復。 – TIm
當你var_dump()$ dbh,$ prep和$ ret時,你會得到什麼?他們是否值你期望?您是否嘗試過使用mysql_ *系列函數運行相同的查詢以進行比較? – jkndrkn