;WITH Recursive_CTE AS (
SELECT
child.ExecutiveId,
CAST(child.ExecutiveName as varchar(100)) BusinessUnit,
CAST(NULL as bigint) ParentUnitID,
CAST(NULL as varchar(100)) ParentUnit,
CAST('' as varchar(100)) LVL,
CAST(child.ExecutiveId as varchar(100)) Hierarchy,
1 AS RecursionLevel
FROM Sales_Executive_level child
WHERE ExecutiveId = 4000 --your Id which you want to get all parent node
UNION ALL
SELECT
child.ExecutiveId,
CAST(LVL + child.ExecutiveName as varchar(100)) AS BusinessUnit,
child.ParentExecutiveID,
parent.BusinessUnit ParentUnit,
CAST('' + LVL as varchar(100)) AS LVL,
CAST(Hierarchy + ':' + CAST(child.ExecutiveId as varchar(100)) as varchar(100)) Hierarchy,
RecursionLevel + 1 AS RecursionLevel
FROM Recursive_CTE parent
INNER JOIN Sales_Executive_level child ON child.ParentExecutiveID = parent.ExecutiveId
)
SELECT * FROM Recursive_CTE ORDER BY Hierarchy
OPTION (MAXRECURSION 300);
可能重複[如何找到在SQL Server表的表列的所有孩子?(http://stackoverflow.com/questions/12625775/how-to-find-all-child-of- a-table-column-in-sql-server-table) – cadrell0
@ cadrell0。我需要父母和孩子爲任何給定的ID。 –