2016-09-27 46 views
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使用DefaultHttpClientConnection發送http發佈請求。是否有可能重用http連接?例如,實例化並設置連接並將套接字綁定到該連接,然後將其分配給該類中的靜態字段。然後對於每個函數調用發送一個http文章,我只是重複使用我之前設置的相同的DefaultHttpClientConnection。我試圖重複使用它,但我不斷收到HTTPException,說我有無效的協議。如果我實例化一個新的DefaultHttpClientConnection,並在每次發送帖子時設置它,代碼就能正常工作,但每當我嘗試提高效率並重用它時,我都會得到該異常。在類對象中保持HTTPClientConnection打開

這是用Java編寫的。

/* 
    * These settings shall speed up the sending of the http request... 
    * */ 
    BasicHttpParams params = new BasicHttpParams(); 
    //Use HTTP 1.1 so we open a TCP connection per request sent 
    params.setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); 
    //Turn off Nagle's Algorithm to speed things up 
    HttpConnectionParams.setTcpNoDelay(params, true); 
    params.setBooleanParameter(HttpProtocolParams.USE_EXPECT_CONTINUE, false); 
    params.setBooleanParameter(HttpConnectionParams.STALE_CONNECTION_CHECK, false); 
    params.setIntParameter(HttpConnectionParams.SOCKET_BUFFER_SIZE, 8 * 1024); 
    client.setParams(params); 
    DefaultConnectionReuseStrategy connStrategy = new DefaultConnectionReuseStrategy(); 

    HttpResponse resp = null; 
    if (conn == null) 
    { 
    executor = new HttpRequestExecutor(); 
    context = new BasicHttpContext(); 
    httpproc = new BasicHttpProcessor(); 
    /*Set http connection processors, mostly default settings 
    * What these protocols do, can be easily found online ;) */ 
    httpproc.addInterceptor(new RequestContent()); 
    httpproc.addInterceptor(new RequestTargetHost()); 
    // Recommended protocol interceptors 
    httpproc.addInterceptor(new RequestConnControl()); 
    httpproc.addInterceptor(new RequestUserAgent()); 
    httpproc.addInterceptor(new RequestExpectContinue()); 
    } 

    conn = new DefaultHttpClientConnection(); 
    if (!conn.isOpen()) 
    { 
    //Opening the socket 
    try 
    { 
     socket = new Socket(request.getURI().getHost(), request.getURI().getPort()); 
     try 
     { 
     //Bind socket to the connection 
     TTLog.log("connection binding to socket..."); 
     conn.bind(socket, client.getParams()); 
     } 
     catch (IOException e1) 
     { 
     TTLog.log("Failed to bind the socket to the HTTPConnection..."); 
     e1.printStackTrace(); 
     } 
    } 
    catch (UnknownHostException e1) 
    { 
     TTLog.log("The host name is invalid... Hostname: " + request.getURI().getHost()); 
     e1.printStackTrace(); 
    } 
    catch (IOException e1) 
    { 
     TTLog.log("I/O Error when creating socket..."); 
     e1.printStackTrace(); 
    } 
    } 

這裏的例外:

org.apache.http.ProtocolException:不是有效的協議版本:??)»在 org.apache.http.impl.io.AbstractMessageParser大號 .parse(AbstractMessageParser.java:181) 在 org.apache.http.impl.AbstractHttpClientConnection.receiveResponseHeader(AbstractHttpClientConnection.java:185) 在 org.apache.http.protocol.HttpRequestExecutor.doReceiveResponse(HttpRequestExecutor.java:284 ) 在 org.apache.http.protocol.HttpRequestExecutor.execute(HttpRequestExecutor.java:126)

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此代碼是我如何設置當前完成的連接。每次調用方法時,我都會創建一個新的DefaultHttpClientConnection。試圖避免這種情況,並將DefaultHttpClientConnection保留在類中的靜態變量上。 –

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對不起。我編輯的問題與我試圖重複使用時得到的異常一樣。 –

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當我執行executor.execute時發生異常。 –

回答

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HTTP是無狀態和無連接的協議。這意味着服務器和客戶端只是滿足當前的請求,然後會話處理,他們忘記了彼此。如果你想保持連接會話,你需要使用Websockets。

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啊...我明白了。謝謝! –

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歡迎光臨!您可以從鏈接進一步閱讀。祝你好運! https://www.tutorialspoint.com/http/http_overview.htm – cagdas