的錯誤是:調用類方法
ReferenceError: $portal is not defined $portal.user = {
我寫的jQuery和普通的JavaScript全新的東西(這是我的第一個Web項目還在學習。)
我。我試圖從Jquery文檔就緒函數中執行$ portal.user.init()函數,但它沒有執行。
我可能會錯過一些東西,請問任何人請幫忙,我應該如何從Jquery &上面調用它的方法。
這裏是我的jQuery代碼
<script type="text/javascript">
$(document).ready(function() {
// Initiate portal..
$portal.user.init(<?php echo $_SESSION['user_id']; ?>,
"<?php echo $_SESSION['user_name']; ?>",
"<?php echo $_SESSION['acc_type']; ?>",
"<?php echo $_SESSION['lang']; ?>",
"<?php echo $_SESSION['first_name']; ?>",
"<?php echo $_SESSION['last_name']; ?>",
"<?php echo $_SESSION['picture']; ?>",
"<?php echo $_SESSION['email']; ?>"
);
});
而且我創造了另一個javascript文件說myweb.js 代碼是這樣的
var _no_profile_pic = "../img/no_profile_pic.png";
/*
* Class : $portal.user
* Desc : Portal User Related Functions
*/
$portal.user = {
user_id: 0,
user_name: '',
acc_type: '',
lang: '',
first_name: '',
last_name: '',
picture: '',
email: '',
/*
* $portal.user.init : Initilise user
* Params :
* user_id - user id
* user_name - login user name
* acc_type - Type of user account like (A - Admin, V - Verified, U - Unverified, D - Deleted)
* lang - User Language like (en-english)
* first_name - User First Name
* last_name - User Last Name
* picture - User Picture URL
* email - User Email Address
* Returns : None
*/
init: function(user_id, user_name, acc_type, lang, first_name, last_name, picture, email)
{
$portal.user.user_id = user_id;
$portal.user.user_name = user_name;
$portal.user.acc_type = acc_type;
$portal.user.lang = lang;
$portal.user.first_name = first_name;
$portal.user.last_name = last_name;
$portal.user.picture = (picture == indef || picture == '' ? _no_profile_pic : picture);
$portal.user.email = email;
alert(this.user_id);
}
};
你可以檢查你的控制檯的任何錯誤,以及是否加載jQuery的lib? – dreamweiver
Whats'indef'? - >'圖片== indef' - 對於未定義或爲空,您可以'.picture = picture || _no_profile_pic,'(即水珠可能是更好的類內放置爲好) –
提示錯誤控制檯 - 的ReferenceError:未定義$門戶 \t $ portal.user = { – SmartDev