我決定通過添加一些更多的功能,修復一些錯誤並添加更多的錯誤,使其成爲一個獨立的項目! yey :)
您可以在這裏找到的項目:http://code.google.com/p/formatting-el/source/browse/trunk/formatting.el
不知道有多少車是這樣的,但在第一眼看到它似乎工作:
(defun directive-end (c)
(member c "csdoxXeg%"))
(defun pp-if-nil (spec)
(position ?\% spec))
(defun pp-list (spec args)
(let ((pos 0) (last 0) (fstring "% ") current seen-^)
(catch 't
(while t
(setq pos (1+ (or (position ?% spec :start pos) -1))
current (aref spec pos))
(unless (and seen-^ (char-equal current ?\}) (null args))
(princ (substring spec last (1- pos))))
(setq last pos pos (1+ pos))
(cond
((char-equal current ?^)
(incf last)
(setq seen-^ t))
((char-equal current ?\{)
(setq pos (+ pos (pp-list (substring spec pos) (car args)))
args (cdr args)
last pos
seen-^ nil))
((char-equal current ?\})
(if args (setq pos 0 last 0)
(throw 't nil)))
((char-equal current ?%)
(setq seen-^ nil last (1+ last))
(write-char ?%))
(t (unless args (error "Not enough argumens for list iteration"))
(setf (aref fstring 1) current)
(princ (format fstring (car args)))
(setq args (cdr args)
seen-^ nil
last
(or (position-if #'directive-end spec :start pos)
pos)))))) pos))
(defun cl-format (spec &rest args)
(with-output-to-string
(let ((pos 0) (last 0) (fstring "% ") current)
(catch 't
(while t
(setq pos (1+ (or (position ?\% spec :start pos) -1))
current (aref spec pos))
(when (= pos 0) (throw 't nil))
(princ (substring spec last (1- pos)))
(setq last pos pos (1+ pos))
(cond
((char-equal current ?^)
(unless args
(setq last (pp-if-nil spec)
pos last)))
((char-equal current ?\{)
(setq pos (+ pos (pp-list (substring spec pos) (car args)))
args (cdr args)
last pos))
((char-equal current ?\})
(error "Unmatched list iteration termination directive"))
((char-equal current ?%)
(write-char ?%)
(incf last))
(t (unless args (error "Not enough argumens"))
(setf (aref fstring 1) current)
(princ (format fstring (car args)))
(setq args (cdr args)
last
(or (position-if #'directive-end spec :start pos)
pos))))
(incf pos))))))
(cl-format "begin: %{%s = %d%^,%}; %% %c %% %{%{%s -> %d%^.%},%}"
'(a 1 b 2 c 3) ?\X '((a 2 b 4 c 6) (a 1 b 3 c 5)))
"begin: a = 1,b = 2,c = 3; % X % a -> 2.b -> 4.c -> 6,a -> 1.b -> 3.c -> 5,"
這試圖複製一些(非常簡單化)~{ ... ~}
指令的Common Lisp-like打印行爲。
是的,這就是謝謝。很明顯,我確實錯過了申請的性質。哇,真是一個很棒的功能! –