我需要具有給定屬性ID的用戶,例如Property.id = $id
belongsTo如何與多個hasMany一起使用包含cakephp 3.x
我想構建此查詢。
$sql = "SELECT p.address1, p.address2, p.address3, p.postcode,
u.email, u.fullname
c.company_name,
tc.created,
tn.active
FROM property AS p
LEFT JOIN tenancy AS tc ON tc.property_id = p.id
LEFT JOIN tenant AS tn ON tn.tenancy_id = tc.id
LEFT JOIN users AS u ON u.id = tn.user_id
WHERE p.id = $id
AND p.active = 1
AND tc.active = 1
AND tn.active = 1
AND u.active = 1
";
這是我協會:
// Tenants
class TenantTable extends Table
{
public function initialize(array $config)
{
$this->table('tenant');
$this->displayField('id');
$this->primaryKey('id');
$this->addBehavior('Timestamp');
$this->belongsTo('Users', [
'foreignKey' => 'user_id',
'joinType' => 'INNER'
]);
$this->belongsTo('Tenancies', [
'foreignKey' => 'tenancy_id',
'className' => 'tenancy',
'joinType' => 'INNER'
]);
// Users
class UsersTable extends Table
{
public function initialize(array $config)
{
$this->table('users');
$this->displayField('name');
$this->hasMany('Tenants', [
'foreignKey' => 'user_id',
'foreignKey' => 'tenants'
]);
}
// Tenancies
class TenancyTable extends Table
{
public function initialize(array $config)
{
parent::initialize($config);
$this->table('tenancy');
$this->displayField('id');
$this->primaryKey('id');
$this->addBehavior('Timestamp');
$this->belongsTo('Properies', [
'foreignKey' => 'property_id',
'className' => 'property'
]);
$this->belongsTo('Company', [
'foreignKey' => 'company_id'
]);
$this->hasMany('Tenant', [
'foreignKey' => 'tenancy_id',
'className' => 'tenant'
]);
// Properties
class PropertyTable extends Table
{
public function initialize(array $config)
{
parent::initialize($config);
$this->table('property');
$this->displayField('id');
$this->primaryKey('id');
$this->addBehavior('Timestamp');
$this->belongsTo('Company', [
'foreignKey' => 'company_id'
]);
$this->hasMany('Tenancies', [
'foreignKey' => 'property_id',
'className' => 'tenancy'
]);
}
我能得到的hasMany關聯,但是當涉及到拿到屬於關聯的用戶來說,它告訴我,租戶不與用戶相關聯。協會如何設置,他們是否正確。我從PropertyTable運行以下ORM。
$query = $this->find()
->select([
'Property.id', 'Property.company_id', 'Property.address1', 'Property.address2', 'Property.address3','Property.postcode',
'Tenancies.id', 'Tenancies.property_id', 'Tenancies.created', 'Tenancies.stage', 'Tenancies.landlord_offer_sent',
'Company.id', 'Company.company_name',
'Tenants.id', 'Tenants.user_id', 'Tenants.stage',
'Users.id', 'Users.email', 'Users.fullname'
])
->where(['Property.id' => $id])
->contain(['Company', 'Tenancies'])
->leftJoinWith('Tenancies', function(\Cake\ORM\Query $query) {
return $query->where([
'Tenancies.active' => 1,
]);
})
->contain(['Tenancies.Tenants'])
->leftJoinWith('Tenancies.Tenants', function(\Cake\ORM\Query $query) {
return $query->where([
'Tenants.active' => 1,
]);
})
/*======= The problem starts from here =========*/
->contain(['Tenancies.Tenants.Users'])
->leftJoinWith('Tenancies.Tenants.Users', function(\Cake\ORM\Query $query) {
return $query->where([
'Users.active' => 1,
]);
});
任何幫助pelase
僅僅因爲你認爲這些關聯是正確的,那並不意味着這是真的。他們可能是正確的,也可能不是,這裏的人沒有看到他們就無法分辨。在編程世界中,單詞不值得太多,代碼是重要的,所以請儘快,_always_包含所有相關的代碼!也請分享您的調試嘗試(例如,您是否嘗試刪除其他遏制/連接?是否通過租戶表包含/加入用戶失敗?等等)。最後但並非最不重要的是,請始終提及您的確切CakePHP版本。 – ndm
謝謝你的隊友。當然我會更新答案 – Fury
@ndm關聯更新 – Fury