的Java減去本地時間

Question

我有兩個LocalTime對象：

LocalTime l1 = LocalTime.parse("02:53:40"); 
LocalTime l2 = LocalTime.parse("02:54:27"); 

我如何在它們之間找到分鐘不同？

Answer 1

使用until或between，由api

import java.time.LocalTime; 
import static java.time.temporal.ChronoUnit.MINUTES; 

public class SO { 
    public static void main(String[] args) { 
     LocalTime l1 = LocalTime.parse("02:53:40"); 
     LocalTime l2 = LocalTime.parse("02:54:27"); 
     System.out.println(l1.until(l2, MINUTES)); 
     System.out.println(MINUTES.between(l1, l2)); 
    } 
} 

Answer 2

你可以這樣做：

long dif = Math.abs (l1.getLocalMillis() - l2.getLocalMillis()); 
TimeUnit.MINUTES.convert (dif, TimeUnit.MILLISECONDS); 

Answer 3

我這樣做與ChronoUnit

long minutesBetween = ChronoUnit.MINUTES.between(l1,l2); 

例

LocalTime localTime=LocalTime.now(); 
    LocalTime localTimeAfter5Minutes=LocalTime.now().plusMinutes(5); 
    Long minutesBetween=ChronoUnit.MINUTES.between(localTime,localTimeAfter5Minutes); 
    System.out.println("Diffrence between time in munutes : "+minutesBetween); 

輸出

Diffrence between time in munutes : 5 

Answer 4

由於Java 8，你可以使用Duration類描述。我認爲這給出了最優雅的解決方案：

long elapsedMinutes = Duration.between(l1, l2).toMinutes();