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我不太得到下面右邊的代碼,但我有一個下拉菜單下面,我想它下面顯示這些值:如何顯示在下拉正確的選項下拉菜單並保留選項顯示
1
1/2
2
2/3
3
3/4
4
4/5
...
10
現在,我也希望能夠保持後所選擇的選項進行提交,我已經嘗試了下面這段代碼,但問題是,它是唯一的顯示值1/2, 2/3, 3/4, 4/5...
等
foreach ($years as $year) {
if ($validSubmission && $year == $getduration) {
if ($year != $max_year) {
$nextYear = $year + 1;
$durationHTML .= "<option value='" . $year . "' selected='selected'>$year/$nextYear</option>".PHP_EOL;
}else{
$durationHTML .= "<option value='" . $year . "' selected='selected'>$year</option>".PHP_EOL;
}
}else{
if ($year != $max_year) {
$nextYear = $year + 1;
$durationHTML .= "<option value='" . $year . "'>$year/$nextYear</option>".PHP_EOL;
}else{
$durationHTML .= "<option value='" . $year . "'>$year</option>" . PHP_EOL;
}
}
}
的origanl代碼是下面這樣的地方顯示正確的選項,但沒有執行$ validS ubmission變量,以便它不保存提交頁面後選擇了該選項:
foreach ($years as $year) {
$durationHTML .= "<option>$year</option>".PHP_EOL;
if ($year != $max_year) {
$nextYear = $year + 1;
$durationHTML .= "<option>$year/$nextYear</option>".PHP_EOL;
}
}
$durationHTML .= '</select>';
下面的代碼並保持展示提交後的選擇,但在值之間不顯示與/
值:
foreach ($years as $year) {
if ($validSubmission && $year == $getduration) {
$durationHTML .= "<option value='" . $year . "' selected='selected'>$year</option>" . PHP_EOL;
} else {
$durationHTML .= "<option value='" . $year . "'>$year</option>" . PHP_EOL;
}
}
但試圖結合這兩個代碼沒有奏效,那就是我的問題