的NSString燒焦我的[16]

Question

我有NSString的，如：

NSString *str = @"225,0,190,169,236,236,113,97,43,102,217,8,113,201,50,45"; 

我怎樣才能將其轉換爲字符數組，如下圖所示：

char keyPtr[16] = {225,0,190,169,236,236,113,97,43,102,217,8,113,201,50,45} 

誰能幫助！

感謝

Answer 1

NSString *input = @"225,0,190,169,236,236,113,97,43,102,217,8,113,201,50,45"; 
char output[16]; 

NSArray *elements = [input componentsSeparatedByString:@","]; 
NSAssert([elements count] == 16, @"Input has wrong number of elements"); 
unsigned index = 0; 
for (NSString *element in elements) { 
    int value = [element intValue]; 
    NSAssert(value >= 0 && value <= 255, @"Element is invalid"); 
    output[index++] = (char)value; 
} 

注意：你應該使用int[]，而不是char[]，對於output。

Answer 2

NSString *str = @"225,0,190,169,236,236,113,97,43,102,217,8,113,201,50,45"; 
NSArray *array = [str componentsSeparatedByString:@","]; 

然後在用這個循環或東西添加到您的字符數組：

char* myLilChar = [[array objectAtIndex:i] UTF8String]; 

乾杯:)

Answer 3

如果你想爲你說的是​​，使用下面

NSString *str = @"225,0,190,169,236,236,113,97,43,102,217,8,113,201,50,45"; 
NSArray *array = [str componentsSeparatedByString:@","]; 
unsigned char keyPtr[array.count]; 
for(int i=0;i<array.count;i++) 
    keyPtr[i] = (unsigned char)[[array objectAtIndex:i] intValue];