Android Volley POST JSONObject與int，字符串和jsonobjects

Question

怎麼了

我想發佈在我的服務器JSONObject。

我已經嘗試了一些代碼，我就發現堆棧：

 String url = "http://10.0.2.2:8080/order"; 
    try { 
     RequestQueue requestQueue = Volley.newRequestQueue(this); 
     String URL = "http://10.0.2.2:8080/order"; 
     JSONObject jsonBody = new JSONObject(); 
     jsonBody.put("waiterId", 1); 
     jsonBody.put("tableNumber", 4); 
     jsonBody.put("remark", "asd"); 
     jsonBody.put("products", new JSONObject()); 
     final String requestBody = jsonBody.toString(); 

     StringRequest stringRequest = new StringRequest(Request.Method.POST, URL, new Response.Listener<String>() { 
      @Override 
      public void onResponse(String response) { 
       Log.i("VOLLEY", response); 
      } 
     }, new Response.ErrorListener() { 
      @Override 
      public void onErrorResponse(VolleyError error) { 
       Log.e("VOLLEY", error.toString()); 
      } 
     }) { 
      @Override 
      public String getBodyContentType() { 
       return "application/json; charset=utf-8"; 
      } 

      @Override 
      public byte[] getBody() throws AuthFailureError { 
       try { 
        return requestBody == null ? null : requestBody.getBytes("utf-8"); 
       } catch (UnsupportedEncodingException uee) { 
        VolleyLog.wtf("Unsupported Encoding while trying to get the bytes of %s using %s", requestBody, "utf-8"); 
        return null; 
       } 
      } 

      @Override 
      protected Response<String> parseNetworkResponse(NetworkResponse response) { 
       String responseString = ""; 
       if (response != null) { 
        responseString = String.valueOf(response.statusCode); 
        // can get more details such as response.headers 
       } 
       return Response.success(responseString, HttpHeaderParser.parseCacheHeaders(response)); 
      } 
     }; 

     requestQueue.add(stringRequest); 
    } catch (JSONException e) { 
     e.printStackTrace(); 
    } 

我收到提示：

E/Volley: [275] BasicNetwork.performRequest: Unexpected response code 400 for http://10.0.2.2:8080/order E/VOLLEY: com.android.volley.ServerError

或者這樣：

String url = "http://10.0.2.2:8080/order"; 
    JSONObject jsonObject = new JSONObject(); 
    try { 
     jsonObject.put("waiterId", 1); 
     jsonObject.put("tableNumber", 1); 
     jsonObject.put("remark", "zamowienie"); 
     jsonObject.put("products", new JSONObject()); 
    } catch (JSONException e) { 
     e.printStackTrace(); 
    } 

    JsonObjectRequest jsonObjReq = new JsonObjectRequest(
      Request.Method.POST, url, jsonObject, 
      new Response.Listener<JSONObject>() { 
       @Override 
       public void onResponse(JSONObject response) { 
        Log.d(TAG, response.toString()); 
       } 
      }, new Response.ErrorListener() { 

     @Override 
     public void onErrorResponse(VolleyError error) { 
      // As of f605da3 the following should work 
      NetworkResponse response = error.networkResponse; 
      if (error instanceof ServerError && response != null) { 
       try { 
        String res = new String(response.data, 
          HttpHeaderParser.parseCharset(response.headers, "utf-8")); 
        // Now you can use any deserializer to make sense of data 
        JSONObject obj = new JSONObject(res); 
       } catch (UnsupportedEncodingException e1) { 
        // Couldn't properly decode data to string 
        e1.printStackTrace(); 
       } catch (JSONException e2) { 
        // returned data is not JSONObject? 
        e2.printStackTrace(); 
       } 
      } 
     } 
    }) { 
     @Override 
     public Map<String, String> getHeaders() throws AuthFailureError { 
      HashMap<String, String> headers = new HashMap<String, String>(); 
      headers.put("Content-Type", "application/json; charset=utf-8"); 
      return headers; 
     } 
    }; 

    Singleton.getInstance(this).addToRequestQueue(jsonObjReq); 

錯誤：

E/Volley: [275] BasicNetwork.performRequest: Unexpected response code 400 for http://10.0.2.2:8080/order

在第二個我發現小費earse「內容類型」，但沒有任何改變。

早些時候我添加使用郵差的目的，這樣的： 「tableNumber」 3：3， 「備註」：[] ：

{ 「waiterId」 「orderRemark」， 「產品」 }

什麼問題？也許我很難加入「產品」。如何添加多個'產品'或發佈沒有'產品'的JSON？

謝謝！我試過把JSONObject改爲jsonObject = new JSONObject（「{\」waiterId \「：3，\」tableNumber \「：3，\」remark \「：\」orderRemark \「，\」products \「：[]}」）;.現在我沒有代碼400問題。這只是沒有發佈新的元素。它不顯示任何錯誤消息：<（與兩個代碼）

編輯2： 我試過其他方法。它沒有工作。

class AsyncT extends AsyncTask<Void,Void,Void> { 

@Override 
protected Void doInBackground(Void... params) { 

    try { 
     Log.d("A","1"); 
     JSONObject jsonObject = new JSONObject(); 
     try { 
      jsonObject.put("waiterId", 1); 
      Log.d("A","2"); 
      jsonObject.put("tableNumber", 1); 
      jsonObject.put("remark", "zamowienie"); 
      jsonObject.put("products", new JSONObject()); 
     } catch (JSONException e) { 
      e.printStackTrace(); 
     } 

     URL url = new URL("http://10.0.2.2:8080/order"); 
     URLConnection urlConn; 
     DataOutputStream printout; 
     DataInputStream input; 
     urlConn = url.openConnection(); 
     urlConn.setDoInput (true); 
     urlConn.setDoOutput (true); 
     urlConn.setUseCaches (false); 
     urlConn.setRequestProperty("Content-Type","application/json"); 
     urlConn.setRequestProperty("Host", "android.schoolportal.gr"); 
     urlConn.connect(); 

     printout = new DataOutputStream(urlConn.getOutputStream()); 
     printout.writeBytes(URLEncoder.encode(jsonObject.toString(),"UTF-8")); 
     printout.flush(); 
     printout.close(); 

    } catch (MalformedURLException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 

    return null; 
} 

Answer 1

使用simplified coding例子，它的工作原理是鼓勵優良，易於