如何在Fedora上啓用Python的unicode？

Question

我想在Fedora 23上編譯MGTAXA，但是我得到python的這個錯誤需要是2.2或更高版本（安裝2.7.10），並且需要啓用unicode。

問題

誰能告訴我，我需要做的，使Python的Unicode的Fedora的23，如何讓它看到，Python是至少2.2？

[root@5a86e481e3cd build]# make -f ../Makefile 

"BOOST_INC_DIR=/include" 
mkdir -p /mgtaxa/build/.deps; /usr/bin/g++ -O3 -fPIC -g -I/mgtaxa/include -I/include -I -I/usr/lib64/python2.7/site-packages/numpy/core/include -MM -o /mgtaxa/build/.deps/py_num_util.d /mgtaxa/src/py_num_util.cpp && cp /mgtaxa/build/.deps/py_num_util.d /mgtaxa/build/.deps/py_num_util.P && sed -e 's/#.*//' -e 's/^[^:]*: *//' -e 's/ *\\$//' -e '/^$/ d' -e 's/$/ :/' </mgtaxa/build/.deps/py_num_util.d>> /mgtaxa/build/.deps/py_num_util.P && rm /mgtaxa/build/.deps/py_num_util.d 
In file included from /usr/include/boost/python/detail/prefix.hpp:13:0, 
       from /usr/include/boost/python/args.hpp:8, 
       from /usr/include/boost/python.hpp:11, 
       from /mgtaxa/include/mgtaxa/py_num_util.hpp:21, 
       from /mgtaxa/src/py_num_util.cpp:16: 
/usr/include/boost/python/detail/wrap_python.hpp:78:2: error: #error Python 2.2 or higher is required for this version of Boost.Python. 
#error Python 2.2 or higher is required for this version of Boost.Python. 
^
In file included from /usr/include/numpy/ndarraytypes.h:4:0, 
       from /usr/include/numpy/ndarrayobject.h:17, 
       from /usr/include/numpy/noprefix.h:9, 
       from /mgtaxa/include/mgtaxa/py_num_util.hpp:22, 
       from /mgtaxa/src/py_num_util.cpp:16: 
/usr/include/numpy/npy_common.h:301:2: error: #error Must use Python with unicode enabled. 
#error Must use Python with unicode enabled. 
^
../Makefile:287: recipe for target 'py_num_util.o' failed 
make: *** [py_num_util.o] Error 1 
[root@5a86e481e3cd build]# 

Answer 1

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'andreyto-mgtaxa-8175a98'：創建一個 「的Fedora 23的Makefile」：$ mkdir build2 && cd build2/ && cmake ../

然後：$ make：這裏沒有錯誤的Fedora 23 - x86_64的。

# make install：你得到/usr/local/bin/{ mgt-glm-build-icm, mgt-glm-build-fixed, mgt-glm-score-fixed, mgt-glm-simple-score }。

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