如何處理REST中的@OneToMany關係

Question

我正在設計一個允許執行一些基本操作的小型REST應用程序。到目前爲止好，我有以下@Entity稱爲Client需要與@Entity沿側堅持叫Loan：

客戶：

@Entity 
@Table(name = "clients") 
public class Client{ 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    @Column(name = "CLIENT_ID") 
    private Long id; 

    private String name; 
    private String surname; 
    private String email; 
    private String phone; 

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "client") 
    private Set<Loan> loans; 

    public Client() {} 

    public Client(Long id, String name, String surname, String email, String phone) { 
     this.id = id; 
     this.name = name; 
     this.surname = surname; 
     this.email = email; 
     this.phone = phone; 
    } 

    // getters/setters 

} 

貸款：

@Entity 
@Table(name = "loans") 
public class Loan{ 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private Long id; 

    @ManyToOne(fetch = FetchType.LAZY) 
    @JoinColumn(name = "CLIENT_ID") 
    private Client client; 

    @Temporal(TemporalType.DATE) 
    private Date startDate = new Date(); 

    @Temporal(TemporalType.DATE) 
    private Date originTerm; 

    private Float maxPossibleAmount; 

    private String notes; 

    public Loan() {} 

    public Loan(Long id, Client client, Date startDate, Date originTerm, Float maxPossibleAmount, String notes) { 
     this.id = id; 
     this.client = client; 
     this.startDate = startDate; 
     this.originTerm = originTerm; 
     this.maxPossibleAmount = maxPossibleAmount; 
     this.notes = notes; 
    } 

// getters/setters 
} 

註冊客戶通過郵遞員完美地工作，但我無法理解如何註冊貸款一個特定的客戶。在試圖這樣做，PostMan拒絕與以下消息註冊新的貸款：

{ "timestamp": 1504429329213, "status": 400, "error": "Bad Request", "exception": "org.springframework.http.converter.HttpMessageNotReadableException", "message": "JSON parse error: Can not construct instance of com.reborn.xxx.backend.models.Client: no int/Int-argument constructor/factory method to deserialize from Number value (1); nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not construct instance of com.reborn.xxx.backend.models.Client: no int/Int-argument constructor/factory method to deserialize from Number value (1)\n at [Source: java.io.PushbackInputStream@121b34b; line: 3, column: 12] (through reference chain: com.reborn.xxx.backend.models.Loan[\"client\"])", "path": "/api/loans/add" }

LoanController：

@RestController 
@RequestMapping(value = "/api/loans") 
public class LoanController extends BaseController { 

    @Autowired 
    private LoanService loanService; 

    @RequestMapping(value = "/add", method = RequestMethod.POST, consumes = MediaType.APPLICATION_JSON_VALUE) 
    public ResponseEntity registerLoan(@RequestBody Loan loan) { 
     Loan regLoan = loanService.registerLoan(loan); 
     if(regLoan == null) { 
      return new ResponseEntity(HttpStatus.INTERNAL_SERVER_ERROR); 
     } 
     return new ResponseEntity(HttpStatus.CREATED); 
    } 
} 

任何想法如何實現這一目標？

UPDATE1：

ClientRepository：

@Repository 
public interface ClientRepository extends JpaRepository<Client, Long>{ 
} 

LoanRepository：

@Repository 
public interface LoanRepository extends JpaRepository<Loan, Long> { 
} 

JSON添加客戶（工程）：

{ 
"id": 1, 
"name": "Arthur", 
"surname": "Doyle", 
"phone": 777458642, 
"email": "adoyle@imperial.com" 
} 

JSON提供貸款給特定的客戶端（失敗）：

{ 
    "id": 1, 
    "client": "http://loacalhost:8080/api/clients/find/1", 
    "startDate": 20170902, 
    "originTerm": 20170902, 
    "maxPossibleAmount": 5555.0000, 
    "notes": null 
} 

Answer 1

你Loan與Client有關。所以，如果你想創建一個貸款客戶端使用該有效載荷：

POST http://loacalhost:8080/api/loans 
{ 
    "originTerm": ... 
    "maxPossibleAmount": ... 
    "notes": ... 
    "client": "http://loacalhost:8080/api/clients/1" 
} 

定製控制器是不必要的。

P.S.將@JsonIgnoreProperties("loans")添加到Loan.client以避免堆棧溢出異常...

P.P.S.在@OneToMany默認情況下，fetch參數爲FetchType.LAZY，因此您可以避開它。