我有以下代碼。如何獲得fork()中execvp的錯誤?
我的問題是在代碼
int main() {
....
if ((uproc.pid = fork()) == -1) {
return -1;
}
if (uproc.pid == 0) {
/* child */
const char *argv[3];
int i = 0;
argv[i++] = "/bin/sh";
argv[i++] = "/my/script.sh";
argv[i++] = NULL;
execvp(argv[0], (char **) argv);
exit(ESRCH);
} else if (uproc.pid < 0)
return -1;
/* parent */
int status;
while (wait(&status) != uproc.pid) {
DD(DEBUG,"waiting for child to exit");
}
// If /my/script.sh exit accidentally in some place with error.
// can I catch this error right here?
......
}
你通過wait函數進入狀態變量。 –
它可能是萬一我的問題的答覆 – MOHAMED
狀態始終爲0,沒有錯誤,萬一有腳本 – MOHAMED