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我是新來的Xcode和斯威夫特,但我想我最好:) 我需要一點幫助。我已經寫了這個代碼到目前爲止...但我有一個問題,我不知道如何解決它... 嗯,我的問題是,我無法檢查兩個變量是否相等。更確切地說,我想檢查「fileAudio」號碼是否與應用中顯示的照片號碼相同。如何檢查來自不同函數的兩個變量是否相等?
我還需要一些幫助來顯示兩個隨機圖片(leftImage和rightImage)和「playSound」按鈕以鏈接到它們中的一個。此時......我只能將它與左圖像鏈接起來。
var soundFiles: [String] = [
"s0",
"s1",
"s2",
"s3",
"s4",
"s5",
"s6",
"s7",
"s8",
"s9"
]
var images1: [UIImage] = [
UIImage(named: "foto0.png")!,
UIImage(named: "foto1.png")!,
UIImage(named: "foto2.png")!,
UIImage(named: "foto3.png")!,
UIImage(named: "foto4.png")!,
UIImage(named: "foto5.png")!,
UIImage(named: "foto6.png")!,
UIImage(named: "foto7.png")!,
UIImage(named: "foto8.png")!
]
var images2: [UIImage] = [
UIImage(named: "foto0.png")!,
UIImage(named: "foto1.png")!,
UIImage(named: "foto2.png")!,
UIImage(named: "foto3.png")!,
UIImage(named: "foto4.png")!,
UIImage(named: "foto5.png")!,
UIImage(named: "foto6.png")!,
UIImage(named: "foto7.png")!,
UIImage(named: "foto8.png")!
]
var happySad: [UIImage] = [
UIImage(named: "sad.png")!,
UIImage(named: "happy.png")!
]
var currentImageIndex = 0
var currentImage2Index = 0
var player: AVAudioPlayer!
var ran1:Int = 0
var ran2:Int = 0
@IBOutlet weak var leftImage: UIImageView!
@IBOutlet weak var rightImage: UIImageView!
@IBOutlet weak var sh: UIImageView!
@IBAction func playSound(_ sender: Any) {
let fileaudio:String = "s"+String(ran1)
let soundFilePath = Bundle.main.url(forResource: fileaudio, withExtension: ".m4a")!
player = try! AVAudioPlayer(contentsOf: soundFilePath)
player.prepareToPlay()
player.play()
}
@IBAction func nextImages(_ sender: Any) {
ran1 = Int(arc4random_uniform(7) + 1)
ran2 = Int(arc4random_uniform(6) + 2)
let imageName1:String = "foto"+String(ran1)
leftImage.image = UIImage.init(named: imageName1)
let imageName2:String = "foto"+String(ran2)
rightImage.image = UIImage.init(named: imageName2)
leftImage.isUserInteractionEnabled = true
self.view.addSubview(leftImage)
let gesture1 = UITapGestureRecognizer(target: self, action: #selector(ViewController.singleTap1))
leftImage.addGestureRecognizer(gesture1)
sh.image = UIImage(named: "question")
rightImage.isUserInteractionEnabled = true
self.view.addSubview(rightImage)
let gesture2 = UITapGestureRecognizer(target: self, action: #selector(ViewController.singleTap2))
rightImage.addGestureRecognizer(gesture2)
}
func singleTap1() {
if currentImageIndex == ran1 {
print("\(currentImageIndex)")
sh.image = UIImage(named: "happy.png")
} else {
print("\(currentImageIndex)")
sh.image = UIImage(named: "sad.png")
}
}
func singleTap2() {
if ran1 == ran2 {
sh.image = UIImage(named: "happy.png")
} else {
sh.image = UIImage(named: "sad.png")
}
}
謝謝你,拉杜
我不想在playSound中產生一個隨機數。我有兩個圖像(左和右)和一個按鈕,playSound。我需要將playSound按鈕鏈接到兩個圖像中的一個(不總是相同)。當我點擊playSound按鈕時,我聽到一個音頻,例如狗吠聲。然後使用必須選擇代表聲音的圖像(左或右)。你能幫我做這件事嗎?請:) –
看看我編輯的答案。 – the4kman
非常感謝你!它的功能就像是一種魅力:D 我可以問你,如何在打開應用程序時讓它顯示2張圖像?現在,當我打開應用程序..我只看到playSound按鈕和nextImages按鈕。如果我點擊playSound,因爲我打開應用程序..它崩潰......錯誤是「預計發現零...」再次感謝! –