'if語句'中的PHP time（）未傳遞給MySql查詢？

Question

if($_SESSION['periode']){ 

    if($_SESSION['periode'] == 'Today'){ 
    $xdate = time() - (1 * 24 * 60 * 60); 
    $ydate = time(); 
    } 
    if($_SESSION['periode'] == 'Yesterday'){ 
    $xdate = time() - (2 * 24 * 60 * 60); 
    $ydate = time() - (1 * 24 * 60 * 60); 
    } 
    if($_SESSION['periode'] == 'This week'){ 
    $xdate = time() - (7 * 24 * 60 * 60); 
    $ydate = time() - (2 * 24 * 60 * 60); 
    } 
    if($_SESSION['periode'] == 'Older'){ 
    $xdate = 0; 
    $ydate = time() - (7 * 24 * 60 * 60); 
    } 
    else{ 
    $xdate = 0; 
    $ydate = time(); 
    } 
} 
else { 
$xdate = 0; 
$ydate = time(); 
} 

$tweets = mysql_query("SELECT * FROM messages WHERE content LIKE '%$search%' 
AND content LIKE '%$region%' 
AND time BETWEEN $xdate AND $ydate ORDER BY id DESC LIMIT 10"); 

問題：所有消息都是從數據庫中選擇的，而不僅僅是$ xdate和$ ydate之間的消息。

但是，如果我在else語句中手動填充unix時間段（並且不要定義$ _SESSION ['periode']），則會從DB中選取正確的消息。這是怎麼回事？？

Answer 1

if($_SESSION['periode'] == 'Older'){ 
    $xdate = 0; 
    $ydate = time() - (7 * 24 * 60 * 60); 
    } 
else{ 
    $xdate = 0; 
    $ydate = time(); 
    } 

此代碼將始終設置$ ydate時間（）和$ xdate爲0，如果$ _SESSION [「periode」]是不是「舊」，因爲這是其他相關的正上方，如果。 您需要使用ELSEIF，而不是如果

代碼必須

if($_SESSION['periode']){ 

    if($_SESSION['periode'] == 'Today'){ 
    $xdate = time() - (1 * 24 * 60 * 60); 
    $ydate = time(); 
    } 
    elseif($_SESSION['periode'] == 'Yesterday'){ 
    $xdate = time() - (2 * 24 * 60 * 60); 
    $ydate = time() - (1 * 24 * 60 * 60); 
    } 
    elseif($_SESSION['periode'] == 'This week'){ 
    $xdate = time() - (7 * 24 * 60 * 60); 
    $ydate = time() - (2 * 24 * 60 * 60); 
    } 
    elseif($_SESSION['periode'] == 'Older'){ 
    $xdate = 0; 
    $ydate = time() - (7 * 24 * 60 * 60); 
    } 
    else{ 
    $xdate = 0; 
    $ydate = time(); 
    } 
} 
else { 
$xdate = 0; 
$ydate = time(); 
}