混亂裝配線$ LEA 0xffffffe8（％EBP）$

Dump of assembler code for function ckpass: 
0x0804851e <ckpass+0>: push %ebp 
0x0804851f <ckpass+1>: mov %esp,%ebp 
0x08048521 <ckpass+3>: sub $0x38,%esp 
0x08048524 <ckpass+6>: movl $0x10,0x8(%esp) 
0x0804852c <ckpass+14>: movl $0x0,0x4(%esp) 
0x08048534 <ckpass+22>: lea 0xffffffe8(%ebp),%eax 
0x08048537 <ckpass+25>: mov %eax,(%esp) 
0x0804853a <ckpass+28>: call 0x80483dc <_init+136> 
0x0804853f <ckpass+33>: lea 0xffffffe8(%ebp),%eax 
0x08048542 <ckpass+36>: mov %eax,(%esp) 
0x08048545 <ckpass+39>: call 0x804839c <_init+72> 
*0x0804854a <ckpass+44>: lea 0xffffffe8(%ebp),%eax* 
0x0804854d <ckpass+47>: mov %eax,0x4(%esp) 
0x08048551 <ckpass+51>: lea 0xffffffd8(%ebp),%eax 
0x08048554 <ckpass+54>: mov %eax,(%esp) 
0x08048557 <ckpass+57>: call 0x8048571 <hashpass> 
0x0804855c <ckpass+62>: lea 0xffffffd8(%ebp),%eax 
0x0804855f <ckpass+65>: movl $0x80486e8,0x4(%esp) 
0x08048567 <ckpass+73>: mov %eax,(%esp) 
0x0804856a <ckpass+76>: call 0x804838c <_init+56> 
0x0804856f <ckpass+81>: leave 
0x08048570 <ckpass+82>: ret

這是

int ckpass() 
{ 
    char a[____]; 
    char b[____]; 
    memset(_________, _____, _____); 
    gets(________); 
    hashpass(b, a); 
    return strcmp(________, good_hash); 
}

究竟什麼lea 0xffffffe8(%ebp),%eax手段拆卸？

我想LEA S（％EBP），％eax中等於EAX = EPB + S

我在谷歌搜索，這表示，它是指緩衝器。

但在這個例子中，我有緩衝區a和緩衝區b，我怎麼能區分它們？

來源

2013-12-10 Timothy Leung

這意味着eax：= ebp -16。反彙編器無法區分有符號和無符號常量。該命令將堆棧中某些變量的地址加載到eax中。

來源

2013-12-10 17:35:46

混亂裝配線$ LEA 0xffffffe8（％EBP）$

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