組合2選擇在一個

我有一個查詢在mysql中工作完美。組合2選擇在一個

 $result =mysql_query(" 
      SELECT a.IDN, c.Name_F, c.Name_L, d.Url_photo, 
        (SELECT COUNT(*) 
         FROM Messages AS e 
         WHERE e.IDN = a.IDN    
        ) AS mes_new , 
        (SELECT LEFT(s.Messages,25) 
         FROM Messages AS s 
         WHERE s.Time= (SELECT MAX(k.Time) 
         FROM Messages AS k 
         WHERE k.IDN = a.IDN) 

        ) AS latest 
      FROM offers AS a 
        LEFT JOIN info AS c 
       ON a.IDN = c.IDN 
        LEFT OUTER JOIN photos AS d 
       ON c.IDN = d.IDN AND d.Flag_av='1' 

      Where a.IDN_with='$IDN' AND a.Status='2'  
     ");

但我也有一個國際化域名，需要做出類似的另一個選擇。類似的東西：

  $result =mysql_query(" 
      SELECT a.IDN, c.Name_F, c.Name_L, d.Url_photo, 
        (SELECT COUNT(*) 
         FROM Messages AS e 
         WHERE e.IDN = a.IDN    
        ) AS mes_new , 
        (SELECT LEFT(s.Messages,25) 
         FROM Messages AS s 
         WHERE s.Time= (SELECT MAX(k.Time) 
         FROM Messages AS k 
         WHERE k.IDN = a.IDN) 

        ) AS latest 
      FROM users AS a 
        LEFT JOIN info AS c 
       ON a.IDN = c.IDN 
        LEFT OUTER JOIN photos AS d 
       ON c.IDN = d.IDN AND d.Flag_av='1' 

      Where a.IDN='$active' 
     ");

因此，大家可以看到只更改表（從報價到用戶）和條件（在哪裏），但有可能使其在一個選擇？作爲雙選我想過UNION，因爲如果IDN將在兩個表中，該行可以重複，我不需要它。但是我想再一次選擇它。可能嗎？

來源

2016-02-26 alex_mike

的聯盟不必須重複。如果選擇1個聯盟選擇2個相同的行不必須重複（如果查詢結果行都是不同的，你將有2列），UNION ALL必須重複 – jrey

是，這是我的意思是工會不會顯示雙排，這是好的，問題是如何從這兩個選擇一個。 –

如果你有..選擇x，1從A其中P UNION選擇x，2從B其中Q.你有2行爲同一個「行」，你可以看到2行..和1或2你可以知道源 – jrey

嗯，我想通了我的自我，因爲用戶表具有所有用戶，我會採取他們的所有行與更復雜的條件。第一次測試結果很好。如果你看到錯誤或有更好的變種請分享）））謝謝。

 $result =mysql_query(" 
      SELECT a.IDN, c.Name_F, c.Name_L, d.Url_photo, 
        (SELECT COUNT(*) 
         FROM Messages AS e 
         WHERE e.IDN = a.IDN    
        ) AS 'mes_new' , 
        (SELECT LEFT(s.Messages,25) 
         FROM Messages AS s 
         WHERE s.Time= (SELECT MAX(k.Time) 
         FROM Messages AS k 
         WHERE k.IDN = a.IDN) 

        ) AS latest 
      FROM users AS a 
        LEFT JOIN offers AS r 
       ON a.IDN = r.IDN 
        LEFT JOIN info AS c 
       ON a.IDN = c.IDN 
        LEFT OUTER JOIN photos AS d 
       ON c.IDN = d.IDN AND d.Flag_av='1' 

      Where (r.IDN_with='$IDN' AND r.Status='2') OR a.IDN='$active'  
     ");

來源

2016-02-26 15:03:02

組合2選擇在一個

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