如何解碼android系統

JSON這是我的JSON數據如何解碼android系統

[{"FeedbackId":"1","Phoneid":"9774d56d682e549c","feedbackdate":"2011\/9 \/24","GuestName":"sdf","Address":"sdf","Phone":"456","Email":"sdf","suggestion":"sdf","grievances":"sdf","visitAgain":"0","purposeofvisit":"sdf","flag":"1"},{"FeedbackId":"2","Phoneid":"9774d56d682e549c","feedbackdate":"","GuestName":"sdf","Address":"sdf","Phone":"456","Email":"sdf","suggestion":"sdf","grievances":"sdf","visitAgain":"0","purposeofvisit":"sdf","flag":"1"},{"FeedbackId":"3","Phoneid":"9774d56d682e549c","feedbackdate":"","GuestName":"sdf","Address":"sdf","Phone":"456","Email":"sdf","suggestion":"sdf","grievances":"sdf","visitAgain":"0","purposeofvisit":"sdf","flag":"1"},{"FeedbackId":"4","Phoneid":"9774d56d682e549c","feedbackdate":"2011\/9 \/24","GuestName":"sdf","Address":"dsf","Phone":"456","Email":"sdf","suggestion":"sf","grievances":"sdf","visitAgain":"0","purposeofvisit":"sdf","flag":"1"},{"FeedbackId":"5","Phoneid":"9774d56d682e549c","feedbackdate":"2011\/9 \/24","GuestName":"sdf","Address":"dsf","Phone":"456","Email":"sdf","suggestion":"sf","grievances":"sdf","visitAgain":"0","purposeofvisit":"sdf","flag":"1"},{"FeedbackId":"6","Phoneid":"9774d56d682e549c","feedbackdate":"","GuestName":"xcv","Address":"xcv","Phone":"89","Email":"xcv","suggestion":"xcv","grievances":"xcv","visitAgain":"1","purposeofvisit":"","flag":"1"},{"FeedbackId":"7","Phoneid":"9774d56d682e549c","feedbackdate":"","GuestName":"gfhj","Address":"ghj6678","Phone":"678","Email":"ghjgh","suggestion":"678fgh","grievances":"fgh","visitAgain":"0","purposeofvisit":"sdf","flag":"1"}]

如何解碼呢？

來源

2011-09-26 Piyush

可能重複[Json解碼在Android]（http://stackoverflow.com/questions/4604657/json-decoding-in-android） – DhruvPathak

但我有所有不同的data.how decode.i看到鏈接，但我不能理解 – Piyush

你應該能夠使用org.json包進行解碼。從here：

String json = "{" 
     + " \"query\": \"Pizza\", " 
     + " \"locations\": [ 94043, 90210 ] " 
     + "}"; 

JSONObject object = (JSONObject) new JSONTokener(json).nextValue(); 
String query = object.getString("query"); 
JSONArray locations = object.getJSONArray("locations");

只需使用自己的JSON，而不是他們的。

來源

2011-09-26 06:32:11 Femi

你也可以使用JSONObject（String）構造函數：'JSONObject obj = new JSONObject（json）;' – hrnt

如何解碼android系統

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