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我試圖讓一個php api請求簡單地粘貼到pastebin，我在http://pastebin.com/api找到一個例子，它是相當海峽，所以我不認爲會有任何麻煩。但這個例子似乎並沒有奏效。我不斷收到響應PasteBin API錯誤？不允許簡單的發佈
Bad API request, invalid api_option
但是你可以清楚地看到它設置它創建的字符串中api_option=paste ...
，並在文件中，它說
Creating A New Paste, [Required Parameters]
Include all the following POST parameters when you request the URL:
1. api_dev_key - which is your unique API Developers Key.
2. api_option - set as 'paste', this will indicate you want to create a new paste.
3. api_paste_code - this is the text that will be written inside your paste.
Leaving any of these parameters out will result in an error.
所以... 。我認爲它看起來不錯，除了它提供的例子。
任何人有任何想法這裏發生了什麼？
<?php
$api_dev_key = '1234'; // your api_developer_key
$api_paste_code = 'some random text to test'; // your paste text
$api_paste_private = '0'; // 0=public 1=private
$api_paste_name = 'savelogtest'; // name or title of your paste
$api_paste_expire_date = '10M';
$api_paste_format = 'php';
$api_user_key = ''; // if invalid key or no key is used, the paste will be create as a guest
$api_paste_name = urlencode($api_paste_name);
$api_paste_code = urlencode($api_paste_code);
$url = 'http://pastebin.com/api/api_post.php';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, 'api_option=paste&api_user_key='.$api_user_key.'&api_paste_private='.$api_paste_private.'&api_paste_name='.$api_paste_name.'&api_paste_expire_date='.$api_paste_expire_date.'&api_paste_format='.$api_paste_format.'&api_dev_key='.$api_dev_key.'&api_paste_code='.$api_paste_code.'');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_VERBOSE, 1);
curl_setopt($ch, CURLOPT_NOBODY, 0);
$response = curl_exec($ch);
echo $response;
?>