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我有下面的代碼行彈出DIV的形式:使用按鈕
<?php foreach($prescription as $process){?>
<button id="issue"> <?php echo $process['medname'];?> </button>
<?php }?>
在按一下按鈕,下面的DIV形式應該彈出
<div id="dialog-form" title="Create new user">
<p class="validateTips">All form fields are required.</p>
<form action="<?php echo base_url()?>phamarcy/issues" method="post">
<fieldset>
<table>
<tr>
<th>Batch Number</th>
<th>Quantity Requested </th>
<th>Selling Price (Kshs:)</th>
<th>Patients Name</th>
<th>Requested By</th>
</tr>
<tr>
<td><select name="item_id" onChange="ChooseContact(this)"id="drug_id">
<option value=""></option>
<?php foreach($prescription as $drugs){?>
<option value="<?php echo $drugs['medname']."|".$drugs['total_quantity']."|".$drugs['expiry_date']."|".$drugs['selling_mark_up_price']."|".$drugs['amount']."|".$drugs['Patients_Name']."|".$drugs['unit_cost']?>"><?php echo $drugs['batch_number']?></option>
<?php }?>
</select>
</td>
<input type="text" name="batch_number" id="batch_number" value="" size="1" />
<input type="text" name="item_id" id="item_id" value="" size="1" />
<input type="text" name="opening_bal" id="opening_bal" value="">
<td><input type="text" name="batch_no" id="batch_no" value="" size="1" disabled="disabled"/></td>
<td><input type="text" name="exp_date" id="exp_date" value="" size="1" disabled="disabled"/></td>
<td><input type="text" name="opening" id="opening" value="" size="1" disabled="disabled" /></td>
<td><input type="text" name="issues" id="issues" value="" size="1" /></td>
<td><input type="text" name="closing_bal" id="closing_bal" value="" size="1"/></td>
<td><input type="text" name="service" id="service" value="" disabled="disabled">
<input type="hidden" name="service_point" id="service_point" value=""/>
</td>
</tr>
<tr>
<td><input type="submit" value="Issue">
</td>
</table>
</fieldset>
</form>
</div>
從下面的腳本這是應該從細節打開上面的div:
<script>
$(function() {
$("#dialog-form").dialog({
autoOpen: false,
height: 300,
width: 1600,
modal: true,
buttons: {
Cancel: function() {
$(this).dialog("close");
}
},
close: function() {
//allFields.val("").removeClass("ui-state-error");
}
});
$(".issue")
.button()
.click(function() {
$("#dialog-form").dialog("open");
});
});
</script>
當我嘗試按一下按鈕,就沒有響應。有沒有一種方法,我怎麼可以讓一個按鈕彈出時,在它PHP數據點擊?
你不能創建多個具有相同ID的按鈕。嘗試改變這種類=「問題」,並看看是否有幫助 –