2012-05-23 25 views
-2
Array 
(
[data] => Array 
    (
     [0] => Array 
      (
       [name] => Sujay John 
       [id] => 765972231 
      ) 

     [1] => Array 
      (
       [name] => Bhawesh Kumar 
       [id] => 820284831 
      ) 

     [2] => Array 
      (
       [name] => Deepak Sharma 
       [id] => 1054741730 
      ) 

     [3] => Array 
      (
       [name] => Raman Steta 
       [id] => 1093844232 
      ) 

     [4] => Array 
      (
       [name] => Rohit Sharma 
       [id] => 1101853912 
      ) 

     [5] => Array 
      (
       [name] => Rakesh Sharma 
       [id] => 1128223845 
      ) 

我要像輸出:PHP解析

name= Sujay John 
id= 765972231 

[name] => Deepak Sharma 
[id] => 1054741730 

像....只有名稱和用戶的ID。

+0

所以什麼問題? – Sumant

+0

我找不出代碼。使用圖形api我已經將所有代碼轉儲到原始文件中,但無法弄清如何從文件轉儲中提取有用的信息並將該內容存儲在數據庫中 –

+0

@KshitijSood http://php.net/arrays – Gordon

回答

0
foreach($level01['data'] as $dataArray){ 
    echo 'name='.$dataArray['name'].' id='.$dataArray['id'].; 
} 

希望幫助或者我的問題錯了...