0
我正在玩twitter API,我試圖解析json輸出。但不知何故,我做錯了什麼,我沒有得到我想要的。從解析的JSON輸出中獲取對象時遇到問題
在這種情況下,我用PHP編寫。開始循環通過數組和screen_name和文本正在相應地工作。
foreach ($statuses as $obj) {
$screen_name = filter_var($obj->user->screen_name, FILTER_SANITIZE_STRING);
$text = filter_var($obj->text, FILTER_SANITIZE_STRING);
$urls = filter_var($obj->entities->urls->url, FILTER_SANITIZE_URL);
}
的JSON陣列輸出:
array (
0 =>
stdClass::__set_state(array(
'created_at' => 'Fri Oct 07 15:31:01 +0000 2016',
'text' => 'test',
'entities' =>
stdClass::__set_state(array(
'hashtags' =>
array (
0 =>
stdClass::__set_state(array(
'text' => '30Under30',
'indices' =>
array (
0 => 36,
1 => 46,
),
)),
),
'symbols' =>
array (
),
'user_mentions' =>
array (
),
'urls' =>
array (
0 =>
stdClass::__set_state(array(
'url' => 'https://Forbes.com',
'expanded_url' => 'https://twitter.com/i/web/status/784415744427687936',
'display_url' => 'twitter.com/i/web/status/7…',
'indices' =>
array (
0 => 117,
1 => 140,
),
)),
),
)),
'source' => 'Sprinklr',
'in_reply_to_screen_name' => NULL,
'user' =>
stdClass::__set_state(array(
'id' => 91478624,
'screen_name' => 'test',
'url' => 'http://Forbes.com',
'entities' =>
stdClass::__set_state(array(
'url' =>
stdClass::__set_state(array(
'urls' =>
array (
0 =>
stdClass::__set_state(array(
'url' => 'http://Forbes.com',
'expanded_url' => 'http://forbes.com',
'display_url' => 'forbes.com',
'indices' =>
array (
0 => 0,
1 => 22,
),
)),
),
)),
'description' =>
stdClass::__set_state(array(
'urls' =>
array (
0 =>
stdClass::__set_state(array(
'url' => 'http://Forbes.com',
'expanded_url' => 'http://Forbes.com',
'display_url' => 'Forbes.com',
'indices' =>
array (
0 => 28,
1 => 48,
),
)),
),
)),
)),
'protected' => false,
'notifications' => false,
)),
'geo' => NULL,
'lang' => 'en',
)),
)
將很高興有一個你想要的結果的例子。我的猜測只是傳遞第二個參數爲真json_decode($ string,true)'。 http://php.net/manual/en/function.json-decode.php –
我想要第一個''url'=>'https:// Forbes.com','參數。我認爲它圍繞第32行。對我來說,它看起來像路徑是entities-> urls-> url。然而這是行不通的 – RvdM
'urls'是一個數組,所以你需要'$ obj-> entities-> url [0] - > url' – Barmar