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我有一段代碼(imageupload.php),其中php假設上傳文件到服務器並將數據插入數據庫。如何創建一個與此代碼關聯的html表格
<?php
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
die();
}
$result = 0;
//UPLOAD IMAGE FILE
move_uploaded_file($_FILES["fileImage"]["tmp_name"], "ImageFiles/" . $_FILES["fileImage"]["name"]);
$result = 1;
//INSERT INTO IMAGE DATABASE TABLE
$imagesql = "INSERT INTO Image (ImageFile) VALUES (?)";
if (!$insert = $mysqli->prepare($imagesql)) {
// Handle errors with prepare operation here
}
//Dont pass data directly to bind_param store it in a variable
$insert->bind_param("s", $img);
//Assign the variable
$img = 'ImageFiles/' . $_FILES['fileImage']['name'];
$insert->execute();
$insertimagequestion->execute();
//IF ANY ERROR WHILE INSERTING DATA INTO EITHER OF THE TABLES
if ($insert->errno) {
// Handle query error here
}
$insert->close();
}
?>
但我想創建html表單來關聯這個,但我從來沒有在html中創建文件輸入。有誰知道如何創建可以與此相關的html表單嗎?
我想要一個html代碼,以便我可以測試上面的代碼,然後能夠測試任何錯誤,如果有的話。
你可能會有所幫助:http://php.net/manual/en/features.file-upload.post-method.php – andrewsi