2014-11-08 29 views
0

我有這樣的PHP代碼從數據庫activity獲取數據:獲取數據,並創建所需的JSON格式

try { 

$dateString = '09.03.2014'; 
$startDate = new DateTime($dateString); 
$endDate = clone $startDate; 
$startDate = $startDate->format("U") . PHP_EOL; 
$period = new DateInterval('P1M'); 

$endDate->add($period); 
$endDate = $endDate->format("U") . PHP_EOL; 

$interval = new DateInterval('P1D'); 
$sql = <<<EOD 
SELECT timestamp_day,name FROM activity WHERE timestamp_day BETWEEN $startDate AND $endDate 
ORDER BY timestamp_day 
EOD; 
$data = $db->query($sql)->fetchAll(PDO::FETCH_ASSOC); 
$output = ['data' => $data]; 
$jsonTable = json_encode($output); //$date->format("U") . PHP_EOL;//format your date to timestamp here 


    } catch(PDOException $e) { 
     echo 'ERROR: ' . $e->getMessage(); 
    } 
    echo $jsonTable; 

此代碼給我從日期到最新的數據,我得到這個JSON:

data: [{timestamp_day:1394319600, name:Meeting}, {timestamp_day:1394319600, name:Car repair},…] 
0: {timestamp_day:1394319600, name:Meeting} 
1: {timestamp_day:1394319600, name:Car repair} 
2: {timestamp_day:1394406000, name:Travel} 
3: {timestamp_day:1394492400, name:Work} 
4: {timestamp_day:1394578800, name:Vacation} 

現在(從Chrome瀏覽器控制檯複製),你可以看到,我有一個從一些日期兩條記錄(0-1),我希望把同一個對象所以是這樣的:

{timestamp_day:1394319600, name:Meeting, Car repair} 
{timestamp_day:1394406000, name:Travel} 
{timestamp_day:1394492400, name:Work} 
{timestamp_day:1394578800, name:Vacation} 

另外我還有一個問題,我現在可以如何使用這個元素becouse我需要在html代碼中:timestamp_day?

而且日期是不要有我的東東擺在JSON所以記錄是這樣的:

{timestamp_day:1394406000, name:'<a>No data</a>'} 

一些想法?

回答

2

使用GROUP_CONCAT將值從記錄相同的時間戳結合:

SELECT timestamp_day, GROUP_CONCAT(name SEPARATOR ', ') AS name 
FROM activity 
WHERE timestamp_day BETWEEN $startDate AND $endDate 
GROUP BY timestamp_day 
ORDER BY timestamp_day 

附:您應該使用準備好的語句而不是變量替換。

下面介紹如何通過每天使用準備好的語句和組它:

$stmt = $db->prepare(" 
    SELECT DATE(FROM_UNIXTIME(timestamp_day)) AS date, GROUP_CONCAT(name SEPARATOR ', ' ORDER BY timestamp_day) AS name 
    FROM activity 
    WHERE timestamp_day BETWEEN :startDate AND :endDate 
    GROUP BY date 
    ORDER BY date"); 
$stmt->bindParam(':startDate', $startDate); 
$stmt->bindParam(':endDate', $endDate); 
$stmt->execute(); 
$data = $stmt->fetchAll(); 
+0

請在這裏展示在回答如何使用準備好的語句,還你能告訴我如何添加空行,如果不存在用於數據那天:{timestamp_day:1394406000,名稱:'沒有數據'} – 2014-11-08 17:59:48

+0

我可以在這裏使用間隔,以檢查timestamp_day的日間隔不是每一秒... – 2014-11-08 18:04:19

相關問題