Android JSON POST，然後回覆

-2

我可以通過JSON檢索listview中的數據，但我想顯示與用戶登錄相關的數據，因此我必須將用戶名發送到PHP腳本。我不知道如何將用戶名發佈到PHP腳本，然後從Web服務器獲得響應。Android JSON POST，然後回覆

private class GetFixture extends AsyncTask<Void, Void, Void> { 

    @Override 
    protected void onPreExecute() { 
     super.onPreExecute(); 
    } 
    @Override 
    protected Void doInBackground(Void... arg) { 


     ServiceHandler serviceClient = new ServiceHandler(); 
     Log.d("url: ", "> " + URL_ITEMS); 
     String json = serviceClient.makeServiceCall(URL_ITEMS,ServiceHandler.GET); 
     // print the json response in the log 
     Log.d("Get match fixture resps","> " + json); 
     if (json != null) { 
      try { 
       Log.d("try", "in the try"); 
       JSONObject jsonObj = new JSONObject(json); 
       Log.d("jsonObject", "new json Object"); 
       // Getting JSON Array node 
       matchFixture = jsonObj.getJSONArray(TAG_FIXTURE); 
       Log.d("json aray", "user point array"); 
       int len = matchFixture.length(); 
       Log.d("len", "get array length"); 
       for (int i = 0; i < matchFixture.length(); i++) { 
        JSONObject c = matchFixture.getJSONObject(i); 
        String matchId = c.getString(TAG_MATCHID); 
        Log.d("matchId", matchId); 
        String teamA = c.getString(TAG_TEAMA); 
        Log.d("teamA", teamA); 
        String teamB = c.getString(TAG_TEAMB); 
        Log.d("teamB", teamB); 
        // hashmap for single match 
        HashMap<String, String> matchFixture = new HashMap<String, String>(); 
        // adding each child node to HashMap key => value 
        matchFixture.put(TAG_MATCHID, matchId); 
        matchFixture.put(TAG_TEAMA, teamA); 
        matchFixture.put(TAG_TEAMB, teamB); 
        matchFixtureList.add(matchFixture); 
       } 
      } 
      catch (JSONException e) { 
       Log.d("catch", "in the catch"); 
       e.printStackTrace(); 
      } 
     } else { 
      Log.e("JSON Data", "Didn't receive any data from server!"); 
     } 
     return null; 
    } 


    @Override 
    protected void onPostExecute(Void result) { 
     super.onPostExecute(result); 
     ListAdapter adapter = new SimpleAdapter(
       Doctor_Names.this, matchFixtureList, 
       R.layout.list_item, new String[] { 
       TAG_MATCHID, TAG_TEAMA,TAG_TEAMB 
     } 
       , new int[] { 
       R.id.teamA,R.id.name, 
       R.id.teamB 
     } 
     ); 
     setListAdapter(adapter); 

    }

先生這段代碼完全告訴我從該服務器的所有數據，但我想一些具體的數據，如我要顯示與誰是登錄所以，我要的用戶名傳遞給PHP個人數據腳本，所以不要有想法POST的基礎上的任何東西的網絡，而我可以過濾數據

來源

2016-04-19 Naveed Abbas

你要問一個更具體的問題，你有什麼到目前爲止和你在哪裏卡住了？ – cyroxis

重複[執行獲取/從服務器發佈的JSON響應在Android]（http://stackoverflow.com/questions/31305631/performing-get-post-from-server-for-json-response-in-android）和數十人。你甚至搜索過嗎？ – 323go

我添加了我的帖子先生 –

下面是一個例子：

JSONObject obj = new JSONObject(); 
obj.put("username", "YourUser"); 
HttpUrlConnectionJson.sendHTTPData("http://" + serverAddress + "/api/SomeUserMethod", obj);

HttpUrl ConnectionJson類

public class HttpUrlConnectionJson { 

    private static final String TAG = "HttpUrlConnectionJson"; 

    public static String sendHTTPData(String urlpath, JSONObject json) { 
     HttpURLConnection connection = null; 
     try { 
      URL url=new URL(urlpath); 
      connection = (HttpURLConnection) url.openConnection(); 
      connection.setDoOutput(true); 
      connection.setDoInput(true); 
      connection.setRequestMethod("POST"); 
      connection.setRequestProperty("Content-Type", "application/json"); 
      connection.setRequestProperty("Accept", "application/json"); 
      OutputStreamWriter streamWriter = new OutputStreamWriter(connection.getOutputStream()); 
      streamWriter.write(json.toString()); 
      streamWriter.flush(); 
      StringBuilder stringBuilder = new StringBuilder(); 
      if (connection.getResponseCode() == HttpURLConnection.HTTP_OK){ 
       InputStreamReader streamReader = new InputStreamReader(connection.getInputStream()); 
       BufferedReader bufferedReader = new BufferedReader(streamReader); 
       String response = null; 
       while ((response = bufferedReader.readLine()) != null) { 
        stringBuilder.append(response + "\n"); 
       } 
       bufferedReader.close(); 

       Log.d(TAG, stringBuilder.toString()); 
       return stringBuilder.toString(); 
      } else { 
       Log.e(TAG, connection.getResponseMessage()); 
       return null; 
      } 
     } catch (Exception exception){ 
      Log.e(TAG, exception.toString()); 
      return null; 
     } finally { 
      if (connection != null){ 
       connection.disconnect(); 
      } 
     } 
    } 
}

我希望這幫助

來源

2016-04-19 19:02:15

Android JSON POST，然後回覆

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