如何使用PHP從字符串中刪除子字符串？

Question

鑑於以下字符串

http://thedude.com/05/simons-cat-and-frog-100x100.jpg 

我想用substr或trim（或任何你找到更合適）返回此

http://thedude.com/05/simons-cat-and-frog.jpg 

也就是說，除去-100x100。我需要的所有圖像都會在擴展名之前立即標記爲文件名的末尾。

似乎有對此迴應紅寶石和Python，但不是PHP /特定於我的需要。

How to remove the left part of a string?

Remove n characters from a start of a string

Remove substring from the string

有什麼建議？

Answer 1

如果你想匹配任何寬度/高度值：

$path = "http://thedude.com/05/simons-cat-and-frog-100x100.jpg"; 

    // http://thedude.com/05/simons-cat-and-frog.jpg 
    echo preg_replace("/-\d+x\d+/", "", $path); 

演示：http://codepad.org/cnKum1kd

使用的模式是非常基本的：

/  Denotes the start of the pattern 
-  Literal - character 
\d+ A digit, 1 or more times 
x  Literal x character 
\d+ A digit, 1 or more times 
/ Denotes the end of the pattern

Answer 2

如果-100x100是您嘗試從所有字符串中刪除的唯一字符，爲什麼不使用str_replace？

$url = "http://thedude.com/05/simons-cat-and-frog-100x100.jpg"; 
str_replace("-100x100", "", $url); 

Answer 3

$url = "http://thedude.com/05/simons-cat-and-frog-100x100.jpg"; 
$new_url = str_replace("-100x100","",$url); 

Answer 4

$url = str_replace("-100x100.jpg", '.jpg', $url); 

使用-100x100.jpg作爲防彈解決方案。