重複自我performSelector

我只是徘徊如果有一個簡單的方法重複20秒以下的代碼。如果有，如何？重複自我performSelector

[self performSelector:@selector(move1) withObject:nil afterDelay:0.0]; 
[self performSelector:@selector(move2) withObject:nil afterDelay:0.2]; 
[self performSelector:@selector(move3) withObject:nil afterDelay:0.4]; 
[self performSelector:@selector(move1) withObject:nil afterDelay:0.8]; 
[self performSelector:@selector(move2) withObject:nil afterDelay:0.10]; 
[self performSelector:@selector(move3) withObject:nil afterDelay:0.12];

來源

2012-07-10 Bazinga

按我的意見剛剛嘗試下面這段代碼，

拿一個NSInteger的在你的控制器的.h文件中，這樣，

NSInteger intTmp;

然後在.m文件中調用像這樣的NSTimer方法，

[NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(testMethod:) userInfo:nil repeats:YES];

和寫入選擇這樣

-(void)testMethod:(NSTimer *)pTmpTimer 
{ 
    intTmp += 1; 

    if(intTmp <= 20) 
    { 
     [self performSelector:@selector(move1) withObject:nil afterDelay:0.0]; 
     [self performSelector:@selector(move2) withObject:nil afterDelay:0.2]; 
     [self performSelector:@selector(move3) withObject:nil afterDelay:0.4]; 
     [self performSelector:@selector(move1) withObject:nil afterDelay:0.8]; 
     [self performSelector:@selector(move2) withObject:nil afterDelay:0.10]; 
     [self performSelector:@selector(move3) withObject:nil afterDelay:0.12];  
    } 
    else 
    { 
     [pTmpTimer invalidate]; 
     intTmp = 0; 
    } 
}

從上面的代碼中，TestMethod的將調用20次，並根據您的要求，您的代碼將重複20次..

希望它爲你工作。

編碼愉快..

來源

2012-07-10 08:19:09

20次？ hmmmm。那20秒怎麼樣？ – Bazinga 2012-07-10 08:33:28

請參閱每1秒調用一次的testMethod，以便它將該intTmp遞增20次，並且當intTmp大於20時，它將進入其他條件並且定時器失效。 – 2012-07-10 09:18:14

謝謝你 – Bazinga 2012-07-12 08:30:36

您可以使用NSTimer，並在定時器調用的選擇器內調用下一個適當的移動方法。

你可以使用

+ (NSTimer *)scheduledTimerWithTimeInterval:(NSTimeInterval)seconds target:(id)target selector:(SEL)aSelector userInfo:(id)userInfo repeats:(BOOL)repeats

USERINFO可用於一些數據傳遞到從中選擇可以選擇哪些舉措隨之而來的或移動最近被調用。

NSTimer *myTimer = [NSTimer scheduledTimerWithTimeInterval:0.2 target:self selector:@selector(invokeMove:) userInfo:[NSNumber numberFromInt:1] repeat:NO];

你的選擇可能是：

-(void)invokeMove:(id)nextMove 
{ 
    if ([nextMove isKindOfClass: [NSNumber class]]) 
    { 
     int veryNextMove = 0; 
     switch ([nextMove intValue]) 
     { 
      case 1: 
       veryNextMove = 1; 
      case 2: 
       veryNextMove = 2; 
      case 3: 
       veryNextMove = 3; 
     } 
     if (veryNextMove == 0) 
      return; 
     NSTimer *myTimer = [NSTimer scheduledTimerWithTimeInterval 0.2 target:self selector:@selector(invokeMove:) userInfo:[NSNumber numberFromInt:2] repeat:NO]; 
     //Assuming you use ARC. 
    }   
}

來源

2012-07-10 08:15:36

的NSTimer scheduledTimerWithTimeInterval？ – Bazinga 2012-07-10 08:19:22

我會編輯答案。 – 2012-07-10 08:23:04

與附表1區間，並與在選擇編寫代碼的計時器。

timer = [NSTimer scheduledTimerWithTimeInterval:1 target:self selector:@selector(callMethods) userInfo:nil repeats:YES];

選擇方法

- (void) callMethods { 
     static int i = 0; 
     if(i < 19) { 
      //your code here 
     for(int j=0; j<2 ;j++) { 
      [self performSelector:@selector(move1) withObject:nil afterDelay:(j*8)/10]; 
      [self performSelector:@selector(move2) withObject:nil afterDelay:((j*8)/10)+0.2]; 
      [self performSelector:@selector(move3) withObject:nil afterDelay:((j*8)/10)+0.4]; 
     } 

     } 
     else { 
      i = 0; 
      [timer invalidate]; 
     } 
     i++; 
     }

來源

2012-07-10 09:16:40

-(void)trickShot{ 
[self performSelector:@selector(move1) withObject:nil afterDelay:0.0]; 
[self performSelector:@selector(move2) withObject:nil afterDelay:0.2]; 
[self performSelector:@selector(move3) withObject:nil afterDelay:0.4]; 
[self performSelector:@selector(move1) withObject:nil afterDelay:0.8]; 
[self performSelector:@selector(move2) withObject:nil afterDelay:0.10]; 
[self performSelector:@selector(move3) withObject:nil afterDelay:0.12]; 
[self performSelector:@selector(trickShot) withObject:nil afterDelay:20]; 
}

來源

2015-03-23 09:38:47 johndpope

重複自我performSelector

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