如何更換一個逗號外支架

Question

我有例如文本：

我就喜歡吃餡餅，我想帶着狗出去，我想去游泳（餡餅，狗，游泳）

我需要一個JavaScript正則表達式，與() 之外的新線取代了,現在如果我使用.replace(/,/g, "\n")我會得到：

I would like to eat a pie 
I would like to take the dog out 
I would like to swim(pie 
dog 
out) 

我需要的是：

I would like to eat a pie 
I would like to take the dog out 
I would like to swim(pie,dog,swim) 

Answer 1

您可以使用正則表達式爲負先行（假設括號是平衡和轉義）：

str = str.replace(/,\s*(?![^()]*\))/g, '\n'); 

RegEx Demo

(?![^()]*\))是負先行斷言，我們沒有)字符前面沒有任何(或)之間的字符。

代碼：

var str = 'I would like to eat a pie,I would like to take the dog out, I would like to swim(pie,dog,swim)'; 
 

 
console.log(str.replace(/,\s*(?![^()]*\))/g, '\n'));

Answer 2

匹配的(...)子和匹配，並捕獲在其他情況下,如果第1組匹配檢查後，以新行後替換：

var rx = /\([^)]*\)|(,)\s*/g; 
 
var s = "I would like to eat a pie,I would like to take the dog out, I would like to swim(pie,dog,swim)"; 
 
var result = s.replace(rx, function($0,$1) { 
 
    return $1 ? "\n" : $1; 
 
}); 
 
console.log(result);

該模式匹配：

• \( - 一個)
• | - - 或
• (,) - 第1組一個(
• [^)]* - 比)
• \)其他0+字符：一個,炭
• \s* - 0+空格（以「修剪」線前的空白）。

查看regex demo。