2017-05-04 141 views
0

我有一個問題:我從http://docs.spring.io/spring-security/site/docs/5.0.0.BUILD-SNAPSHOT/reference/htmlsingle/#samples春季安全啓動404

下載的文件,它的我的web.xml:

<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"> 
    <context-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>/WEB-INF/security.xml</param-value> 
    </context-param> 

    <welcome-file-list> 
     <welcome-file>index.jsp</welcome-file> 
    </welcome-file-list> 

    <filter> 
     <filter-name>springSecurityFilterChain</filter-name> 
     <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> 
    </filter> 

    <filter-mapping> 
     <filter-name>springSecurityFilterChain</filter-name> 
     <url-pattern>/*</url-pattern> 
    </filter-mapping> 

    <listener> 
     <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 
    </listener>  
</web-app> 

security.xml文件:

<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:security="http://www.springframework.org/schema/security" xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd"> 
    <security:http auto-config="true"> 
     <security:intercept-url pattern="/products/add" access="ROLE_ADMIN" /> 
     <security:form-login login-page="/login" default-target-url="/products/add" authentication-failure-url="/loginfailed"/> 
     <security:logout logout-success-url="/logout" /> 
    </security:http> 
    <security:authentication-manager> 
     <security:authentication-provider> 
      <security:user-service> 
       <security:user name="Admin" password="Admin123" authorities="ROLE_ADMIN" /> 
      </security:user-service> 
     </security:authentication-provider> 
    </security:authentication-manager> 
</beans> 

我收到錯誤404,如果我嘗試進入我的網站,有什麼不對?

回答

0

您還沒有爲您的應用程序定義任何servlet。嘗試爲該servlet定義DispatherServlet和映射。

0

是否有人可以推薦我任何春季的好教程?因爲我失去了力量。我以前從未遇到.NET或PHP的任何框架問題,但Java冒險活動已經失去動力。我嘗試從教程中的例子,它不工作,這是不正常的。我使用linux和tomcat8,也許在這是問題?