我用spring 4.1開發。我嘗試我的網址與控制器彈簧URL映射的簡單問題
這地圖是我的web.xml文件
<!-- Spring MVC -->
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
這裏的提取物是我的Spring XML文件
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix">
<value>/WEB-INF/pages/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<context:component-scan base-package="orm,orm.impl,web.controller.impl,web.view" />
這裏的提取物的提取物我的控制器文件
package web.controller.impl;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import org.apache.logging.log4j.LogManager;
import org.apache.logging.log4j.Logger;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.beans.factory.annotation.Qualifier;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
import service.CommonManagementService;
import web.view.QuestionItem;
import domain.Question;
@Controller
public class ComboController {
private static final Logger LOGGER = LogManager.getLogger();
@Autowired
@Qualifier("commonManagementService")
private CommonManagementService commonManagementService;
public CommonManagementService getCommonManagementService() {
return this.commonManagementService;
}
@RequestMapping(value = "/unsecure/getQuestion", method = RequestMethod.GET)
public ModelAndView getQuestion(ModelMap model) {
LOGGER.info("debut methode getQuestion");
final List<QuestionItem> results = new ArrayList<QuestionItem>();
final List<Question> questions = this.commonManagementService.getQuestions();
for (final Question question : questions) {
results.add(new QuestionItem(question.getQuestion(), question.getId().toString()));
}
final Map<String, Object> modelToPass = new HashMap<String, Object>();
model.put("items", results);
LOGGER.info("fin methode getQuestion");
return new ModelAndView("jsonResultView", model);
}
public void setCommonManagementService(
CommonManagementService commonManagementService) {
this.commonManagementService = commonManagementService;
}
}
我的應用程序的名稱是tennisArc1600,當我嘗試發送網址 http://localhost:8080/tennisArc1600/unsecure/getQuestion或http://localhost:8080/unsecure/getQuestion 我得到的錯誤404的ressource不可
預先感謝您爲您的建議
喜@flamant,一般來說,如果你是受歡迎的你認爲一個答案解決了你的問題/問題,你應該接受它作爲問題的答案。 –