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比方說,我有以下型號:如何爲對象創建自定義的ReactiveMongo Reader&Writer?
case class Game(var _id: Option[BSONObjectID] = None,
name: String,
genre: Genre.Kind,
var created: Option[DateTime] = None,
var updated: Option[DateTime] = None
)
我想如下存儲的Game
一個實例: {"_id": "ObjectId(12345)", "name": "My Shooter Game", "genre": "Shooter", …}
對於Genre
我想存儲的值作爲一個字符串,但編程我想處理類型而不是價值。
所以這是我想會的工作:
object Genre {
sealed trait Kind
implicit val genreJsonFormat = Json.format[Genre.Kind]
case object Shooter extends Kind {
val name = "Shooter"
override def toString = name
}
def getGenre(genre: String) = genre match {
case Shooter.name => Shooter
// ...
}
implicit object GenreWriter extends BSONDocumentWriter[Genre.Kind] {
def write(genre: Genre.Kind): BSONDocument =
BSONDocument("genre" -> genre.toString)
}
implicit object GenreReader extends BSONDocumentReader[Genre.Kind] {
def read(doc: BSONDocument): Genre.Kind = Genre.getGenre(doc.getAs[String]("genre").get)
}
}
不幸的是,我得到這個編譯錯誤:
No unapply or unapplySeq function found
爲:
implicit val genreJsonFormat = Json.format[Genre.Kind]
任何想法如何,我可以實現那?
建議先閱讀[documentation](https://www.playframework.com/documentation/2.5.x/ScalaJson) – cchantep
'Json.format'不是ReactiveMongo提供的,而是Play JSON – cchantep