parse.com |如何在UITextView上顯示結果？

Question

這是我的測試查詢

PFQuery *lookingForSomething = [PFQuery queryWithClassName:@"AprilMessage"]; 
[lookingForSomething whereKey:@"user" equalTo:[PFUser currentUser]]; 
[lookingForSomething findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) { 

    // nothing here 

for (PFObject *objectFound in objects) { 

     NSLog(@" this is my objectFound", objectFound); 

到目前爲止好，我的NSLog（objectFound）的結果是：

{ 
message = hello world ! ; 
reciever = "<PFUser:WNOmhmrO3L>"; 
user = "<PFUser:WNOmhmrO3L>"; 

我想要做的就是獲取消息字符串「hello世界！「在這裏它顯示在屏幕上， 我做什麼，但它不工作由於某種原因

// same code from before just adding the last lines down there 

PFQuery *lookingForSomething = [PFQuery queryWithClassName:@"AprilMessage"]; 
[lookingForSomething whereKey:@"user" equalTo:[PFUser currentUser]]; 
[lookingForSomething findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) { 

// nothing here 

    for (PFObject *objectFound in objects) { 

    NSLog(@" this is my objectFound", objectFound); 

    // adding this new line 

objectFound[@"message"] = _textChat.text; <-- textChat is a UITextView !!! 

任何想法是我有什麼錯？

Answer 1

您的最後一行是倒退。它應該是，

_textChat.text = objectFound[@"message"]; 

這應該工作假設_textChat和objectFound [@「message」]不是零。