我有一個GridView如下插入數據時的選擇按鈕,用戶點擊GridView的
<asp:GridView ID="gvDoctorList" runat="server" AutoGenerateColumns="False" DataSourceID="SqlDataSource1"
AllowPaging="True" AllowSorting="True"
OnSelectedIndexChanged="gvDoctorList_SelectedIndexChanged" OnRowCommand="gvDoctorList_RowCommand" OnRowDataBound="gvDoctorList_RowDataBound">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<%--<asp:CheckBox runat="server" ID="chk" OnCheckedChanged="chk_CheckedChanged" AutoPostBack="true" />--%>
<asp:Label runat="server" ID="lblPID" Visible="false" Text='<%# Eval("PatientId") %>'></asp:Label>
<asp:Button ID="btnSelect" runat="server" Text="Select" CommandArgument='<%# Eval("PatientId") %>' CommandName = "Select" />
</ItemTemplate>
</asp:TemplateField>
<asp:BoundField DataField="PatientId" HeaderText="PatientId" SortExpression="PatientId" />
<asp:BoundField DataField="firstname" HeaderText="firstname" SortExpression="firstname" />
<asp:BoundField DataField="lastname" HeaderText="lastname" SortExpression="lastname" />
<asp:BoundField DataField="sex" HeaderText="sex" SortExpression="sex" />
</Columns>
</asp:GridView>
<asp:SqlDataSource ID="SqlDataSource1" runat="server" ConnectionString="<%$ ConnectionStrings:MyDatabaseConnectionString %>"
SelectCommand="SELECT [PatientId],[firstname], [lastname], [sex] FROM [PatientDetails]"></asp:SqlDataSource>
<asp:Button ID="btnformatric" runat="server" Text="formatric3d" OnClick="btnformatric_Click" />
背後的GridView rowcommand裏面的代碼是如下
protected void gvDoctorList_RowCommand(object sender, GridViewCommandEventArgs e)
{
if (e.CommandName == "Select")
{
int pID = Convert.ToInt32(e.CommandArgument);
Session["PatientId"] = Convert.ToString(e.CommandArgument);
//Server.Transfer("Patientstaticformatrix.aspx");
string pIDstr = Convert.ToString(Session["PatientId"]);
if (!string.IsNullOrEmpty(pIDstr))
{
int patientID = Convert.ToInt32(pID);
//string connection = System.Configuration.ConfigurationManager.ConnectionStrings["connectionString"].ConnectionString;
string sqlquery = "SELECT * FROM [MyDatabase].[dbo].[PatExam] where PId = '" + patientID + "'";
string connection = System.Configuration.ConfigurationManager.ConnectionStrings["connectionString"].ConnectionString;
using(SqlConnection conn = new SqlConnection(connection))
{
//SqlConnection conn = new SqlConnection(con);
DataSet ds;
ds = new DataSet();
SqlDataAdapter cmpatientexam;
conn.Open();
cmpatientexam = new SqlDataAdapter(sqlquery, conn);
cmpatientexam.Fill(ds, "PatientExam");
TreeNode pidnode = new TreeNode();
pidnode.Text = pIDstr;
foreach (DataRow patrow in ds.Tables["PatientExam"].Rows)
{
//TreeNode tvpatexam = new TreeNode();
//tvpatexam.Text = patrow["PId"].ToString();
//TreeView1.Nodes.Add(tvpatexam);
//for (int i = 0; i < ds.Tables["PatientExam"].Columns["PId"].Count; i++)
//if (patrow["PId"].ToString() != DBNull.Value)
//{
TreeNode childtvpatexam = new TreeNode();
childtvpatexam.Text = patrow["Exam"].ToString();
pidnode.ChildNodes.Add(childtvpatexam);
//break;
//}
//TreeView1.Nodes.Add(tvpatexam);
}
TreeView1.Nodes.Add(pidnode);
ds.Dispose();
cmpatientexam.Dispose();
conn.Close();
conn.Dispose();
}
}
}
}
代碼背後的按鈕單擊事件是
protected void btnformatric_Click(object sender, EventArgs e)
{
foreach (GridViewRow row in gvDoctorList.Rows)
{
Button btn = (Button)row.FindControl("Select");
if (btn != null)
{
string pIDstr = Convert.ToString(Session["PatientId"]);
string exam = ((Button)sender).Text;
SqlCommand cmd = new SqlCommand("INSERT INTO [dbo].[PatExam]([PId],[Exam]) VALUES (@pid,@exam)", con);
if (con.State == ConnectionState.Closed)
{
con.Open();
}
try
{
cmd.Connection = con;
cmd.Parameters.AddWithValue("@pid", pIDstr);
cmd.Parameters.AddWithValue("@exam", exam);
cmd.ExecuteNonQuery();
}
catch (Exception ex)
{
Response.Write("Error Occured: " + ex.Message.ToString());
}
finally
{
con.Close();
cmd.Dispose();
}
}
}
}
我想插入從gridview中選擇的值,使用select按鈕和inse rt該按鈕單擊事件選定的值....但與上述代碼,它不工作...
任何人都可以建議我一些其他的想法或如果可能與這些代碼,然後如何......你能給我它的代碼....非常感謝
我試試你的代碼,我的事要告訴你,我有按鈕不ImageButton的,所以我GridViewRow gvr =(GridViewRow)(((Button)e.CommandSource).NamingContainer);但仍然當我在按鈕單擊事件調試時,btn的值爲空....會發生什麼錯誤....? – Pratik
它工作正常......謝謝 – Pratik