問題與分組項

Question

我有一個列表中的一個問題，我想顯示組和子組（sgroups），是這樣的：

GROUP1 
sgroup1-a 
sgroup1-b 
sgroup1-c 
sgroup1-d 
GROUP2 
sgroup2-a 
sgroup2-b 

但我的代碼返回：

GROUP1 
sgroup1-a 
GROUP1 
sgroup1-b 
GROUP1 
sgroup1-c 
GROUP2 
sgroup2-a 
GROUP2 
sgroup2-b 
sgroup1-d 

所以我有顯示組的名稱。

表結構：

CREATE TABLE IF NOT EXISTS `groupe` (
`id_hm` int(2) NOT NULL AUTO_INCREMENT, 
`groupe_tran` varchar(30) COLLATE utf8_unicode_ci NOT NULL, 
`onoff` enum('0','1') COLLATE utf8_unicode_ci NOT NULL DEFAULT '1' COMMENT '0:no, 1:active', 
`search` enum('0','1') COLLATE utf8_unicode_ci NOT NULL DEFAULT '0' COMMENT 'include in search menu, 0: 0ff, 1: on', 
PRIMARY KEY (`id_hm`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=11 ; 


CREATE TABLE IF NOT EXISTS `sgroupe` (
`id_bm` int(2) NOT NULL AUTO_INCREMENT, 
`id_hm1` tinyint(2) NOT NULL COMMENT 'head menu id', 
`sgroupe_tran` varchar(30) COLLATE utf8_unicode_ci NOT NULL, 
`sgroupe_en` varchar(30) COLLATE utf8_unicode_ci NOT NULL, 
`onoff` enum('0','1') COLLATE utf8_unicode_ci NOT NULL DEFAULT '1' COMMENT '0:no, 1:active', 
`search` enum('0','1') COLLATE utf8_unicode_ci NOT NULL DEFAULT '0' COMMENT 'include in search menu, 0: 0ff, 1: on', 
PRIMARY KEY (`id_bm`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=49 ; 

查詢和PHP代碼：

$sSel = 'SELECT DISTINCT(groupe_tran), sgroupe_tran FROM groupe JOIN sgroupe ON groupe.id_hm = sgroupe.id_hm1 WHERE groupe.search = "1" AND sgroupe.search = "1" AND groupe.onoff = "1" AND sgroupe.onoff = "1"'; 

$sReq = $connexion->query($sSel); 
$sRes = $sReq->fetchAll(); 

echo '<select name="groupe">'; 
foreach ($sRes as $sV) { 

    $groupe_tran = $sV['groupe_tran']; 
    $sgroupe_tran = $sV['sgroupe_tran']; 

    echo '<option value="' . $groupe_tran . '">' . $groupe_tran . '</option>'; 
    echo '<option value="' . $sgroupe_tran . '">' . $sgroupe_tran . '</option>'; 
} 
echo '</select>'; 

Answer 1

假設$groupe_tran是你GROUP1/GROUP2值，你可以保存前$groupe_tran和檢查電流值不相同 -

$sSel = 'SELECT DISTINCT(groupe_tran), sgroupe_tran FROM groupe JOIN sgroupe ON groupe.id_hm = sgroupe.id_hm1 WHERE groupe.search = "1" AND sgroupe.search = "1" AND groupe.onoff = "1" AND sgroupe.onoff = "1"'; 

$sReq = $connexion->query($sSel); 
$sRes = $sReq->fetchAll(); 

// create a previous value 
$previous_groupe_tran = ''; 

echo '<select name="groupe">'; 
foreach ($sRes as $sV) { 

    $groupe_tran = $sV['groupe_tran']; 
    $sgroupe_tran = $sV['sgroupe_tran']; 

    // check if current matches previous, and only print if no match  
    if($groupe_tran != $previous_groupe_tran){ 

     echo '<option value="' . $groupe_tran . '">' . $groupe_tran . '</option>'; 

     // set previous to current 
     $previous_groupe_tran = $groupe_tran; 
    } 

    echo '<option value="' . $sgroupe_tran . '">' . $sgroupe_tran . '</option>'; 
} 
echo '</select>'; 

Answer 2

我把你的榜樣，並添加array_push：

$previous_groupe_tran = array(); 

echo '<select name="hmenu">'; 
foreach ($sRes as $sV) { 

$groupe_tran = $sV['groupe_tran']; 
$sgroupe_tran = $sV['sgroupe_tran']; 

if(!in_array($groupe_tran, $previous_groupe_tran)){ 
array_push($previous_groupe_tran, $groupe_tran); 
print_r($previous_groupe_tran); 
echo '<option value="' . $groupe_tran . '">'.$id_hm.' - ' . $groupe_tran . '</option>'; 
    } 

    echo '<option value="' . $sgroupe_tran . '">'.$id_hm1.' - ' . $sgroupe_tran . '</option>'; 
}