如何選擇一個不可選的列

Question

我在sql server中有一列需要選擇，我不能選擇，但似乎存在。它是隻讀列還是其他問題？希望我在這裏添加了足夠的信息，並將我的列和表的名稱更改爲通用名稱。

SELECT t.name as TName, c.name AS ColName 
FROM sys.columns c 
JOIN sys.tables t ON c.object_id = t.object_id 
WHERE upper(c.name) like '%MY_COLUMN_NAME%' 

TName  ColName  
------  ----------- 
My_Table My_Column 

但是當我嘗試選擇它時，它說它不存在。有沒有解決方法？

select My_Column from My_Table 

Msg 207, Level 16, State 1, Line 9 
Invalid column name 'My_Column'. 

當我嘗試了所有的信息，我得到這個：

SELECT t.name as TName, c.name AS ColName, t.*, c.* 
FROM sys.columns c 
JOIN sys.tables t ON c.object_id = t.object_id 
WHERE upper(c.name) like '%My_Column%' 

TName                               ColName                               name                                object_id principal_id schema_id parent_object_id type type_desc             create_date    modify_date    is_ms_shipped is_published is_schema_published lob_data_space_id filestream_data_space_id max_column_id_used lock_on_bulk_load uses_ansi_nulls is_replicated has_replication_filter is_merge_published is_sync_tran_subscribed has_unchecked_assembly_data text_in_row_limit large_value_types_out_of_row is_tracked_by_cdc lock_escalation lock_escalation_desc           is_filetable object_id name                                column_id system_type_id user_type_id max_length precision scale collation_name                             is_nullable is_ansi_padded is_rowguidcol is_identity is_computed is_filestream is_replicated is_non_sql_subscribed is_merge_published is_dts_replicated is_xml_document xml_collection_id default_object_id rule_object_id is_sparse is_column_set 
-------------------------------------------------------------------------------------------------------------------------------- -------------------------------------------------------------------------------------------------------------------------------- -------------------------------------------------------------------------------------------------------------------------------- ----------- ------------ ----------- ---------------- ---- ------------------------------------------------------------ ----------------------- ----------------------- ------------- ------------ ------------------- ----------------- ------------------------ ------------------ ----------------- --------------- ------------- ---------------------- ------------------ ----------------------- --------------------------- ----------------- ---------------------------- ----------------- --------------- ------------------------------------------------------------ ------------ ----------- -------------------------------------------------------------------------------------------------------------------------------- ----------- -------------- ------------ ---------- --------- ----- -------------------------------------------------------------------------------------------------------------------------------- ----------- -------------- ------------- ----------- ----------- ------------- ------------- --------------------- ------------------ ----------------- --------------- ----------------- ----------------- -------------- --------- ------------- 
My_Table                               My_Column                            My_Table                               1223935682 NULL   20   0    U USER_TABLE             2014-02-19 10:35:44.537 2017-02-11 12:48:13.037 0    0   0     1     NULL      39     0     1    0    0      0     0      0       0     0       0     0    TABLE              0   1223935682 My_Column                            7   104   376   1   1   0  NULL                                1   0    0    0   0   0    0    0      0     0     0    0     0     0    0   0 

（影響1行（S））

Answer 1

你有在具有不同的模式相同名稱的表不同的列？

您的結果看起來像是bit列，而schema_id是20，所以我懷疑它是默認架構（dbo）。但我可能會讀錯，因爲值和標題看起來像是失去了對齊。

select 
    TName = quotename(schema_name(t.schema_id))+'.'+quotename(t.name) 
    , ColName = c.name 
from sys.columns c 
    inner join sys.tables t 
    on c.object_id = t.object_id 
where c.name like '%My_Column%' 

Answer 2

它可能在不同的模式。
嘗試使用以下查詢，因爲這也會爲您提供模式名稱。

SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = 'MY_COLUMN';

這個假設是由於做出這樣的事實，在最後一次查詢的schema_id爲0