PHP代碼打破HTML佈局

Question

我有一個簡單的文件上傳，這感謝stackoverflow現在完全工作，但是當我將PHP代碼複製到我的主佈局，一旦初始化上傳文件，但它是錯誤的格式或大小，它迴應錯誤，它打破了它下面的HTML。我認爲它與「退出」有關。每個回聲之後？但可能是錯誤的。

<?php 
if($_POST['upload']) { 
if($_FILES['image']['name'] == "") 
{ 
    #there's no file name return an error 
    echo "<br/><b>Please select a file to upload!\n</b>"; 
    exit; 
} 
#we have a filename, continue 

#directory to upload to 
$uploads = '/home/habbonow/public_html/other/quacked/photos'; 
$usruploads = 'photos'; 

#allowed file types 
$type_array = array(image_type_to_mime_type(IMAGETYPE_JPEG), image_type_to_mime_type(IMAGETYPE_GIF), image_type_to_mime_type(IMAGETYPE_PNG), 'image/pjpeg'); 

if(!in_array($_FILES['image']['type'], $type_array)) 
{ 
    #the type of the file is not in the list we want to allow 
    echo "<br/><b>That file type is not allowed!\n</b>"; 
    exit; 
} 

$max_filesize = 512000; 
$max_filesize_kb = ($max_filesize/1024); 

if($_FILES['image']['size'] > $max_filesize) 
{ 
    #file is larger than the value of $max_filesize return an error 
    echo "<br/><b>Your file is too large, files may be up to ".$max_filesize_kb."kb\n</b>"; 
    exit; 
} 

$imagesize = getimagesize($_FILES['image']['tmp_name']); 

#get width 
$imagewidth = $imagesize[0]; 
#get height 
$imageheight = $imagesize[1]; 

#allowed dimensions 
$maxwidth = 1024; 
$maxheight = 1024; 

if($imagewidth > $maxwidth || $imageheight > $maxheight) 
{ 
    #one or both of the image dimensions are larger than the allowed sizes return an error 
    echo "<br/><b>Your file is too large, files may be up to ".$maxwidth."px x ".$maxheight."px in size\n</b>"; 
    exit; 
} 

move_uploaded_file($_FILES['image']['tmp_name'], $uploads.'/'.$_FILES['image']['name']) or die ("Couldn't upload ".$_FILES['image']['name']." \n"); 

echo "<br/>The URL to your photo is <b>" . $usruploads . "/" . $_FILES['image']['name'] . "</b>. Please use this when defining the gallery photos"; 

} 

?> 

<form name="uploader" method="post" action="" enctype="multipart/form-data"> 
     <input type="file" name="image" style="width:300px;cursor:pointer" /> 
     <input type="submit" name="upload" value="Upload Image" /> 
</form> 

Answer 1

確實，當你撥打exit;這意味着「立即停止所有處理;該腳本完成」。它後面的任何內容（包括HTML）都不會被解釋。

一個更好的組織是使這個代碼功能，效果：

function uploadMyStuffPlease() { 

    if($_POST['upload']) { 
     if($_FILES['image']['name'] == "") 
     { 
      #there's no file name return an error 
      echo "<br/><b>Please select a file to upload!\n</b>"; 
      return; 
     } 
     #we have a filename, continue 

    // .... 

} 

現在，你可以簡單地調用uploadMyStuffPlease()，這將做盡可能多的處理是可以的，也許在提前返回發生錯誤。無論哪種方式，功能將返回，所以您的腳本的其餘部分（包括該HTML）仍然可以解釋。

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