mysql_close（）預計參數1是資源，空給出

Question

引起錯誤的行是這樣的產品......

mysql_close($con); 

這裏是代碼的整體...

$con=mysqli_connect("localhost","root","pass","db_name"); 
// Check connection 
if (mysqli_connect_errno()) { 
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
} 

$result = mysqli_query($con,"SELECT * FROM medicos"); 


    while($row = mysqli_fetch_array($result)) { 
    echo '.....'; 
    } 



    mysql_close($con); 

Answer 1

該生產線mysql_close($con);必須改變，以mysqli_close($con);

不能互換使用mysql和mysqli功能，例如：

mysqli_connect需要使用mysqli_close

- 也 -

mysql_connect需要使用的mysql_close