切割清單蟒蛇基地

Question

例如：

my_string='ONETWOTHREEFOURFIVESIXSEVENEIGHTNINETEN' 

，以及如何使之成爲

['ONE','TWO','THREE','FOUR','FIVE','SIX','SEVEN','EIGHT','NINE','TEN'] 

我怎樣才能做到這一點有效，但不導入什麼？

Answer 1

假設你知道這可能工作的話長度（你需要更新lengths元組）：

my_string='ONETWOTHREEFOURFIVESIXSEVENEIGHTNINETEN' 
lengths = (3, 3, 5, 4, 4, 3) 

words = [] 
start = 0 
for i in lengths: 
    words.append(my_string[start:start+i]) 
    start += i 

print(words) # ['ONE', 'TWO', 'THREE', 'FOUR', 'FIVE', 'SIX'] 

Answer 2

可以使用match()方法簡單。但在此之前，你需要有與輸出相匹配什麼樣的價值從my_string，如：

var my_string='ONETWOTHREEFOURFIVESIXSEVENEIGHTNINETEN'; 
var one = "ONE"; 
var array = []; 

if(string.match(one)) array.push(one); 

Answer 3

lengths = (3, 3, 5, 4, 4, 3) 

it = iter('ONETWOTHREEFOURFIVESIXSEVENEIGHTNINETEN') 

words = (''.join(next(it) for _ in range(length)) for length in lengths)