MySQL的計數相同的間隔內的行海誓山盟

我有一個表，其中一列是日期：MySQL的計數相同的間隔內的行海誓山盟

+----------+---------------------+ 
|  id |    date | 
+----------+---------------------+ 
|  5 | 2012-12-10 10:12:37 |   
+----------+---------------------+ 
|  4 | 2012-12-10 09:09:55 |   
+----------+---------------------+ 
|  3 | 2012-12-09 21:12:35 |   
+----------+---------------------+ 
|  2 | 2012-12-09 20:15:07 |   
+----------+---------------------+ 
|  1 | 2012-12-09 20:01:42 |   
+----------+---------------------+

我需要什麼，是計數其例如whitin 3小時，以彼此的行。在這個例子中，我想加入第二行的上一行，第四行和第五行的第三行。所以我的輸出應該是這樣的：

+----------+---------------------+---------+ 
|  id |    date | count | 
+----------+---------------------+---------+ 
|  5 | 2012-12-10 10:12:37 |  2 | 
+----------+---------------------+---------+ 
|  3 | 2012-12-09 21:12:35 |  3 | 
+----------+---------------------+---------+

我怎麼能這樣做？

來源

2013-02-11 almax bácsi

那麼，[**你有什麼**]（http：// www .whathaveyoutried.com）？ – Kermit 2013-02-11 19:55:06

我認爲你需要自連接此：（這是未經測試的代碼，以便它可能有一個語法錯誤）

select t.id, t.date, COUNT(t2.id) 
from t left outer join 
    t t2 
    on t.date between t2.date - interval 3 hour and t2.date + interval 3 hour 
group by t.id, t.date

如果你正在嘗試一切分爲3-小時一班，你可以這樣做：

select max(t.date), t.id, count(*) 
from (select t.*, 
      (date(date)*100 + floor(hour(date)/3)*3) as interval 
     from t 
    ) t 
group by interval

來源

2013-02-11 19:58:25

根據問題中的示例，它將返回5行而不是2 ....每個ID的每行... – 2013-02-11 21:28:14

@NitinMidha。。。您的原始*問題*不是關於過濾或分組行，而是關於在3小時內查找計數。你可以每2小時記錄一次，而且它們都會鏈接在一起。我以固定的時間間隔回答了問題。 – 2013-02-11 21:39:10

在他的預期產出中，他將第4行和第5行合併爲第5行，第1,2行和第3行合併爲第3行。 – 2013-02-11 22:22:43

我不知道如何使用我的SQL做到這一點，但我能夠建立一組查詢的SQL Server 2005中，將提供預期的結果。這裏是工作樣本，其非常複雜，可能過於複雜，但這就是我如何能夠得到所需結果：

WITH BaseData AS 
(
    SELECT 5 AS ID, '2012-12-10 10:12:37' AS Date 
    UNION ALL 
    SELECT 4 AS ID, '2012-12-10 09:09:55' AS Date 
    UNION ALL 
    SELECT 3 AS ID, '2012-12-09 21:12:35' AS Date 
    UNION ALL 
    SELECT 2 AS ID, '2012-12-09 20:15:07' AS Date 
    UNION ALL 
    SELECT 1 AS ID, '2012-12-09 20:01:42' AS Date 
), 
BaseDataWithRowNum AS 
(
    SELECT ID,DATE, ROW_NUMBER() OVER (ORDER BY Date DESC) AS RowNum 
     FROM BaseData 
), 
InterRelatedDates AS 
(
    SELECT B1.RowNum AS RowNum1,B2.RowNum AS RowNum2 
     FROM BaseDataWithRowNum B1 
    INNER JOIN BaseDataWithRowNum B2 
     ON B1.Date BETWEEN B2.Date AND DATEADD(hh,3,B2.Date) 
     AND B1.RowNum < B2.RowNum 
     AND B1.ID != B2.ID 
), 
InterRelatedDatesWithinMultipleGroups AS 
(
    SELECT G1.RowNum1,G2.RowNum2 
     FROM InterRelatedDates G1 
     LEFT JOIN InterRelatedDates G2 
     ON G1.RowNum2 = G2.RowNum2 
     AND G1.RowNum1 != G2.RowNum1 
) 


SELECT BN.ID, 
     BN.Date, 
     CountExcludingOriginalGrouppingRecord +1 AS C 
    FROM 
     (
     SELECT RowNum1 AS RowNum,COUNT(1) AS CountExcludingOriginalGrouppingRecord 
      FROM 
       (
       -- If a row was used in only one group then it is ok. use as it is 
       SELECT D1.RowNum1 
        FROM InterRelatedDatesWithinMultipleGroups AS D1 
       WHERE D1.RowNum2 IS NULL 

       UNION ALL 

       -- In case a row was selected in two groups, choose the one with higher date 
       SELECT Min(D1.RowNum1) 
        FROM InterRelatedDatesWithinMultipleGroups AS D1 
       WHERE D1.RowNum2 IS NOT NULL 
       GROUP BY D1.RowNum2 
      ) T 
     GROUP BY RowNum1 
    ) T2 
INNER JOIN BaseDataWithRowNum BN 
    ON BN.RowNum = T2.RowNum

來源

2013-02-11 22:12:07

MySQL的計數相同的間隔內的行海誓山盟

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