seekbar拇指位置不等於進度

Question

我想用拇指創建seekbar而不改變進度。我的搜索欄進度必須與拇指位置分開設置。我該怎麼做？

我應該說，我必須擴展Seekbar並重寫一些方法。但我不明白哪個？哪種方法確定拇指的位置？哪個決定進展？

Please help me!! 
Thanks at advance! 

Answer 1

嘗試使用不同的drawbles 讓我告訴你一個例子：

你code 的.java

import android.os.Bundle; 
import android.app.Activity; 
import android.graphics.drawable.Drawable; 
import android.widget.SeekBar; 

public class MainActivity extends Activity { 
    private SeekBar seekBar1; 

    private SeekBar seekBar2; 
    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 
     seekBar1 = (SeekBar) findViewById(R.id.seekBar1); 
     seekBar2 = (SeekBar) findViewById(R.id.seekBar2); 
     seekBar1.setProgress(15); 
     seekBar2.setProgress(55); 
     Drawable ii = getResources().getDrawable(R.drawable.ii); 
     // Drawable iii = getResources().getDrawable(R.drawable.ii); 
     seekBar1.setThumb(ii); 
     seekBar2.setThumb(ii); 

    } 



} 

您的問題：

你可以做的是simple只是重命名同一繪製這樣的：

import android.os.Bundle; 
import android.app.Activity; 
import android.graphics.drawable.Drawable; 
import android.widget.SeekBar; 

public class MainActivity extends Activity { 
    private SeekBar seekBar1; 

    private SeekBar seekBar2; 
    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 
     seekBar1 = (SeekBar) findViewById(R.id.seekBar1); 
     seekBar2 = (SeekBar) findViewById(R.id.seekBar2); 
     seekBar1.setProgress(15); 
     seekBar2.setProgress(55); 
     Drawable ii = getResources().getDrawable(R.drawable.ii); 
     Drawable iii = getResources().getDrawable(R.drawable.ii); 
     seekBar1.setThumb(ii); 
     seekBar2.setThumb(iii); 

    } 



} 

這就是結果：

希望幫助!! :)