我試圖根據用戶輸入(用戶名)獲取字段值(SecurityQues)。基於用戶輸入獲取字段值
以下是代碼:
$substr=substr($usrnm,0,2);
if($substr=="AC")
{
$res="SELECT SecurityQues FROM reg_ac WHERE UserName=$usrnm";
}
else
{
$res="SELECT SecurityQues FROM reg_indi WHERE UserName=$usrnm";
}
$result = mysql_query($res,$db_handle);
$result = mysql_query($res);
while($row = mysql_fetch_assoc($result))
{
echo $row['SecurityQues'];
}
但我得到以下警告:
警告:mysql_fetch_assoc()預計參數1是資源,布爾在C中給出:\ XAMPP \ htdocs \我的在線120