需要的路線爲我的網頁API 2控制器

Question

我有一個簡單WebApi2控制器返回XML，但我不能用我定義了路由適當加另一種方法：

namespace CBMI.WebAPIservice.Controllers 
{ 
public class MarkersController : ApiController 
{ 
    public HttpResponseMessage Get(int? id) 
    { 
     int i = id.HasValue ? id.Value : 0; 
     XmlDocument docContent = GetXmlDataFromDB(i); 
     return new HttpResponseMessage 
     { 
      Content = new StringContent(docContent.InnerXml.ToString(), Encoding.UTF8, "application/xml") 
     }; 
    } 
    public HttpResponseMessage GetGrantsIS() 
    { 
     XmlDocument docContent = GetXmlDataFromDB(); 
     return new HttpResponseMessage 
     { 
      Content = new StringContent(docContent.InnerXml.ToString(), Encoding.UTF8, "application/xml") 
     }; 

    } 
    public XmlDocument GetXmlDataFromDB() 
    { 
     string connStr = System.Convert.ToString(
       System.Web.Compilation.ConnectionStringsExpressionBuilder.GetConnectionString("MDWConnectionString"), 
       System.Globalization.CultureInfo.CurrentCulture); 
     SqlConnection conn = new SqlConnection(connStr); 
     SqlCommand sqlCmd = new SqlCommand("dbo.FLAS_List_GrantLocationsByAmount_V1", conn); 
     sqlCmd.CommandType = System.Data.CommandType.StoredProcedure; 
     conn.Open(); 
     XmlDocument xmlDoc = new XmlDocument(); 
     XmlReader xmlReader = sqlCmd.ExecuteXmlReader(); 
     if (xmlReader.Read()) 
      xmlDoc.Load(xmlReader); 
     conn.Close(); 
     return xmlDoc; 
    } 
    public XmlDocument GetXmlDataFromDB(int worldAreaID) 
    { 
     string scrambleAward = ""; 
     string connStr = System.Convert.ToString(
       System.Web.Compilation.ConnectionStringsExpressionBuilder.GetConnectionString("MDWConnectionString"), 
       System.Globalization.CultureInfo.CurrentCulture); 
     SqlConnection conn = new SqlConnection(connStr); 
     SqlCommand sqlCmd = new SqlCommand("dbo.FLAS_List_Awards_V1", conn); 
     sqlCmd.CommandType = System.Data.CommandType.StoredProcedure; 
     sqlCmd.Parameters.AddWithValue("@AreaID", worldAreaID); 
     sqlCmd.Parameters.AddWithValue("@Scramble", scrambleAward); 
     conn.Open(); 
     XmlDocument xmlDoc = new XmlDocument(); 
     XmlReader xmlReader = sqlCmd.ExecuteXmlReader(); 
     if (xmlReader.Read()) 
      xmlDoc.Load(xmlReader); 
     conn.Close(); 
     return xmlDoc; 
    } 

} 

}

WebApiConfig.cs

namespace CBMI.WebAPIservice.App_Start 
{ 
// This code file defines the delegate where you should put your Web API configuration code. 

public static class WebApiConfig 
{ 
    public static void Register(HttpConfiguration config) 
    { 
     // Web API routes 
     config.MapHttpAttributeRoutes(); 

     config.Routes.MapHttpRoute 
      (
       name: "WebApi2", 
       routeTemplate: "api/{controller}/{id}" 
      ); 
     config.Routes.MapHttpRoute 
      (
       name: "ApiGrantsIS", 
       routeTemplate: "api/{controller}/{action}" 
      ); 
    } 
} 

}

I C注意瞭解如何更改路由以識別動作，以便調用方法。而是使用以下URL進行瀏覽

CBMI.WebAPIservice/api/markers/GetGrantsIS 

通過Get方法識別該ID沒有值的路由。它然後默認值爲0，它的工作原理，但我需要這個URL調用GetGrantsIS方法。

編輯：嘗試添加屬性路由賦予了新的錯誤

我飾如下：

[Route("api/{controller}/GetGrantsIS")] 
    public HttpResponseMessage GetGrantsIS() 

，現在我得到這樣的：

Server Error in '/CBMI.WebAPIservice' Application. 
 

 
A direct route cannot use the parameter 'controller'. Specify a literal path in place of this parameter to create a route to a controller.

Answer 1

Web Api 2支持REST架構，這意味着它期望您的操作爲GET，POST，PUT，DELETE。

但是，您可以使用attribute routing來獲得所需的結果。

如果你想使用屬性路由，你已經在你的WebApiConfig文件中有該設置。所以，你只需要修改代碼以使用路由屬性，像這樣：

[Route("api/markers/getgrantsis")] 
public HttpResponseMessage GetGrantsIS() 
{ 
    XmlDocument docContent = GetXmlDataFromDB(); 
    return new HttpResponseMessage 
    { 
    Content = new StringContent(docContent.InnerXml.ToString(), Encoding.UTF8, "application/xml") 
    }; 

}