如何隔離「first_name」鍵以在下列對象中輸出其值？

Question

如何隔離first_name鍵以在下列對象中輸出其值？

{ 
    "first_name": "D", 
    "last_name": "N", 
    "phone_number": 1233414234 
} 

Answer 1

您可以使用.或[]

var x = {"first_name":"D","last_name":"N","phone_number": 1233414234}; 
alert(x.first_name); 
alert(x['first_name']); 

參考是here。

編輯

基於在對方的回答評論OP的問題：如果你想通過一個數組對象進行迭代，你可以使用每個。

var array = [{"first_name":"D","last_name":"N","phone_number": 1233414234},{"first_name":"P","last_name":"T","phone_number": 1233414234}]; 
$.each(array, function(idx) { 
    alert(array[idx].first_name); 
}); 

OR

var array = [{"first_name":"D","last_name":"N","phone_number": 1233414234},{"first_name":"P","last_name":"T","phone_number": 1233414234}]; 
$.each(array, function(idx, obj) { 
    alert(obj.first_name); 
}); 

Answer 2

要麼與點符號或括號記號。閱讀更多關於property accessors。

var object = { first_name: "D", last_name: "N", phone_number: 1233414234 }; 
 

 
// dot notation 
 
console.log(object.first_name); 
 
    
 
// bracket notation 
 
console.log(object['first_name']);

對於對象的數組，你可以使用Array#map -

var array = [{"first_name":"D","last_name":"N","phone_number": 1233414234},{"first_name":"P","last_name":"T","phone_number": 1233414234}], 
 
    first_names = array.map(function (a) { 
 
     return a.first_name; 
 
    }); 
 

 
console.log(first_names);