彈出ABAddressBook模式只有電子郵件聯繫人

Question

我想顯示一個模式的ABAddressBook只有註冊了電子郵件的聯繫人。我如何實現這一目標？

我試過這段代碼：

- (IBAction)getContact { 
    // creating the picker 
    ABPeoplePickerNavigationController *picker = [[ABPeoplePickerNavigationController alloc] init]; 

    ABAddressBookRef addressBook = ABAddressBookCreate(); 
    CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook); 
    CFIndex nPeople = ABAddressBookGetPersonCount(addressBook); 

    for(CFIndex emailIndex = 0; emailIndex < nPeople; emailIndex++) { 
     ABRecordRef person = CFArrayGetValueAtIndex(allPeople, emailIndex); 
     ABMutableMultiValueRef emailRef= ABRecordCopyValue(person, kABPersonEmailProperty); 
     int emailCount = ABMultiValueGetCount(emailRef); 
     if(!emailCount) { 
      CFErrorRef error = nil; 
      ABAddressBookRemoveRecord(addressBook, person, &error); 
      if (error) NSLog(@"Error: %@", error); 
     } 
    } 
    picker.addressBook = addressBook; 
    picker.peoplePickerDelegate = self; 
    [self presentModalViewController:picker animated:YES]; 
} 

的列表顯示了我所有的接觸，但「刪除」那些看起來像「NO NAME」，並且有一個名字的人，有一個真實的電子郵件。

Answer 1

我已成功地創建另一個解決方案...

我補充說，至少有一個電子郵件的觸點在陣列......取而代之的是解決方案，着眼於當前的地址簿和刪除的那些的那沒有任何電子郵件。這裏是代碼：

ABAddressBookRef addressBook = ABAddressBookCreate(); 
    CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook); 
    CFIndex nPeople = ABAddressBookGetPersonCount(addressBook); 

    for(CFIndex emailIndex = 0; emailIndex < nPeople; emailIndex++) { 
     ABRecordRef person = CFArrayGetValueAtIndex(allPeople, emailIndex); 
     ABMutableMultiValueRef emailRef= ABRecordCopyValue(person, kABPersonEmailProperty); 
     int emailCount = ABMultiValueGetCount(emailRef); 
     if(!emailCount) { 
      CFErrorRef error = nil; 
      ABAddressBookRemoveRecord(addressBook, person, &error); 
      if (error) NSLog(@"Error: %@", error); 
     } else { 
      ABMultiValueRef emails = ABRecordCopyValue(person, kABPersonEmailProperty); 
      NSString *email = (__bridge NSString *)ABMultiValueCopyValueAtIndex(emails, 0); 
      NSString *name = (__bridge NSString *)(ABRecordCopyValue(person, kABPersonFirstNameProperty)); 

      if (name) { 
       NSMutableDictionary *contactDict = [NSMutableDictionary dictionaryWithObjectsAndKeys: 
              name, @"name", 
              email, @"email", 
              nil]; 
       [self.contactsArray addObject:contactDict]; 
      } 
     } 
    }