1
我正在用PyQt5編寫一個計算器,用戶界面已經完成,但是當我改變QLineEdit的內容時有一個問題。改變它的細節方法是當用戶按下按鈕時調用QLineEdit.setText()
方法。如何在程序運行時更改QPyLineEdit的內容?
但是當我按下PushButton時,程序結束並顯示如下消息:「Process completed with exit code 1」。沒有任何錯誤或警告信息。這是下面的完整程序:
# -*- coding:utf-8 -*-
import sys
from PyQt5.QtWidgets import (QWidget, QGridLayout,
QPushButton, QLineEdit, QVBoxLayout, QApplication, QMessageBox)
class Calculator(QWidget):
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
# grid = QGridLayout()
qvbox = QVBoxLayout()
gridBar = QGridLayout()
gridWidget = QWidget()
numberEdit = QLineEdit()
numberEdit.setReadOnly(True)
names = ["Cls", "Bck", "", "Close",
"7", "8", "9", "/",
"4", "5", "6", "*",
"1", "2", "3", "-",
"0", ".", "=", "+"]
position = [(i, j) for i in range(5) for j in range(4)]
for position, name in zip(position, names):
if name == "":
continue
button = QPushButton(name)
gridBar.addWidget(button, *position)
button.clicked.connect(self.buttonClicked)
qvbox.addWidget(numberEdit)
gridWidget.setLayout(gridBar)
qvbox.addWidget(gridWidget)
self.setLayout(qvbox)
self.move(300, 150)
self.setWindowTitle("Calculator")
self.show()
def buttonClicked(self):
sender = self.sender()
self.dealData(sender.text())
def dealData(self, data):
self.numberEdit.setText(data) # Here, the program exited!!!
print(data) # The output in consle was right.
if __name__ == "__main__":
app = QApplication(sys.argv)
ex = Calculator()
sys.exit(app.exec_())
我在哪裏犯了一個錯誤?
非常感謝你。但是,當我更改代碼後,問題仍然發生。而且我試圖將代碼「self.numberEdit.setReadOnly(True)」更改爲「self.numberEdit.setReadOnly(False)」,問題仍然存在。 – user7102471
@ user7102471。那是因爲你輸入了「SetText」而不是「setText」。無論如何,我已經在我的回答中提出了更好的解決方案。 – ekhumoro
太棒了!有用!感謝您的幫助! – user7102471