1
在我的網站上,用戶有一個'待辦事項'列表。在測驗中獲得最低成績後,該測驗將從用戶的待辦事項中刪除。以下代碼適用於產品,但不適用於通過「商業關係」列出的任何測驗。MySQL查詢不起作用
def not_quizzed_things
taken_company_ids = quizzes_taken.select{|q| q.thing_type == 'BusinessRelationship'}.map{|q| q.thing_id}.uniq
conds = "business_relationships.from_company_id = ? and (business_relationships.legit_quiz_questions_count + c.legit_quiz_questions_count) > 0"
args = [company_id]
unless taken_company_ids.blank?
conds += " and c.id not in (?)"
args << taken_company_ids
end
quiz_companies = BusinessRelationship.find(:all, :joins => "join companies c on c.id = business_relationships.to_company_id", :conditions => [conds]+args, :order => "id", :limit => 0)
quiz_companies = [company] + quiz_companies unless company.legit_quiz_questions_count <= 0 || quizzes_taken.select{|q| q.thing_type == 'Company'}.map{|q| q.thing}.include?(company)
n = 20 - quiz_companies.size
taken_products_retailer_ids = quizzes_taken.select{|q| q.thing_type == 'ProductsRetailer'}.map{|q| q.thing_id}.uniq
conds = "products_retailers.company_id = ? and (p.legit_quiz_questions_count + products_retailers.legit_quiz_questions_count) > 0"
args = [company_id]
unless taken_products_retailer_ids.blank?
conds += " and products_retailers.id not in (?)"
args << taken_products_retailer_ids
end
quiz_products_retailers = ProductsRetailer.find(:all, :joins => "join products p on p.id = products_retailers.product_id", :conditions => [conds]+args, :order => "id", :limit => n)
quiz_companies + quiz_products_retailers
end
控制檯結果:
ruby-1.8.7-p352 :007 > y u.quizzes_taken.last
--- !ruby/object:Quiz
attributes:
thing_id: "213"
created_at: 2012-06-09 20:07:32
end_time: 2012-06-09 20:07:56
current_attempt_id:
thing_type: BusinessRelationship
updated_at: 2012-06-09 20:07:56
order: "2388,2389,2390,2391"
id: "467"
correct_count: "4"
user_id: "392"
attempt_count: "4"
start_time: 2012-06-09 20:07:32
attributes_cache: {}
任何想法或建議,不勝感激!