2013-02-02 68 views
2

的我使用11克Express版本,Eclipse的朱諾,Java 6的持久性,Oracle瘦,ORA-12505,TNS監聽器目前不知道SID

甲骨文啓動並運行甚至試圖立即停機和啓動,但沒有得到SID聽者錯誤

<?xml version="1.0" encoding="UTF-8"?> 
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"> 

    <persistence-unit name="default" transaction-type="RESOURCE_LOCAL"> 
    <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider> 
    <class>com.crspdemo.Employee</class> 
    <properties> 
     <property name="javax.persistence.jdbc.url" value="jdbc:oracle:thin:@localhost:1521:jsfDatabase"/> 
     <property name="javax.persistence.jdbc.password" value="admin"/> 
     <property name="javax.persistence.jdbc.driver" value="oracle.jdbc.driver.OracleDriver"/> 
     <property name="javax.persistence.jdbc.user" value="system"/> 
     <!--<property name="eclipselink.ddl-generation" value="create-tables"/>--> 
    </properties> 
    </persistence-unit> 

</persistence> 

錯誤:

Caused by: javax.persistence.PersistenceException: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.2.0.v20110202-r8913): org.eclipse.persistence.exceptions.DatabaseException 

內部異常:java.sql.SQLException中:監聽拒絕合作並出現以下錯誤nnection: ORA-12505,TNS:監聽器目前不知道SID的連接描述符中給出

LISTNER.ORA

listner.ora

回答

2

嘗試使用默認SID爲XE :

<property name="javax.persistence.jdbc.url" value="jdbc:oracle:thin:@localhost:1521:XE"/> 
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